Q. 44 Show that Equation聽32.27聽for t... [FREE SOLUTION]

Chapter 32: Q. 44 (page 925)

Show that Equation $32.27$ for the phase angle $蠒$ of a series $R L C$ circuit gives the correct result for a capacitor-only circuit.

Short Answer

Expert verified

The expression $蠒 = \tan^{- 1} (\frac{X_{L} - X_{C}}{R})$ for phase angle of series $R L C$ circuit gives correct result for capacitor only circuit.

Step by step solution

Given Information

We are given that the Equation $32.27$ which is $蠒 = \tan^{- 1} (\frac{X_{L} - X_{C}}{R})$ .

We need to prove that this equation for phase angle of series $R L C$ circuit gives correct result for capacitor only circuit.

Explanation

We know equation,

$\tan 蠒 = \frac{V_{L} - V_{C}}{V_{R}} 鈬� \frac{(X_{L} - X_{C})}{R I}$

Here gets canceled so equation can be rewritten as :

$蠒 = \tan^{- 1} (\frac{X_{L} - X_{C}}{R})$

We are also given that , $X_{L} = X_{C} = 0$

From here phase angle becomes $蠒 = \tan^{- 1} (0) = 0 r a d .$

Similarly for $A C$ Inductor circuit conditions are

localid="1649931138237" $R = X_{C} = 0 蠒 = \tan^{- 1} (鈭�) = 蟺 / 2 rad$

Hence proved that it gives correct result for capacitor only circuit.

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91影视

Show that Equation $32.27$ for the phase angle $蠒$ of a series $R L C$ circuit gives the correct result for a capacitor-only circuit.

Short Answer

Step by step solution

Given Information

Explanation

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91影视

Show that Equation32.27for the phase angle蠒of a seriesRLC circuit gives the correct result for a capacitor-only circuit.

Short Answer

Step by step solution

Given Information

Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Linear Momentum

Electric Charge Field and Potential

Modern Physics

Fundamentals of Physics

Fluids

Atoms and Radioactivity

Study anywhere. Anytime. Across all devices.

Show that Equation $32.27$ for the phase angle $蠒$ of a series $R L C$ circuit gives the correct result for a capacitor-only circuit.