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91Ó°ÊÓ

The emf phasor in FIGURE EX32.2 is shown at t=15ms.

a. What is the angular frequency Ó¬? Assume this is the first rotation.

b. What is the instantaneous value of the emf?

Short Answer

Expert verified

The angular frequency Ó¬is 244rad/sand instantaneous value of the emf is-10V.

Step by step solution

01

Part (a) Step 1: Given information

We are given that time t=15ms, Eo=12Vand ∅=150∘(as the phasor rotates anticlockwise towards X-axis)

02

Part (a) Step 2: Calculation

As we know that-

E=E0cos(Ӭt+∅)

Ӭt=180∘+∅Ӭt=180∘+30∘Ӭt=210∘ (as phasor rotates anticlockwise)

Now converting degrees into radian

210∘=210∘π°ù²¹»å180∘=7Ï€°ù²¹»å6

Now,

Ó¬t=7Ï€°ù²¹»å6Ó¬(15×10-3)=7Ï€°ù²¹»å6Ó¬=244rad/s

03

Part (b) Step 1: Given information

We are given that-

E0=12V∅=150∘

04

Part (b) Step 2: Calculation

As we know that peak valueE0=12V will occur when Ó¬t=0

So now in the expression,

E=E0cos(Ӭt+∅)E=12Vcos(0+150∘)E=-10V

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