/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Full body scan, Part I. A news a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Full body scan, Part I. A news article reports that "Americans have differing views on two potentially inconvenient and invasive practices that airports could implement to uncover potential terrorist attacks." This news piece was based on a survey conducted among a random sample of 1,137 adults nationwide, interviewed by telephone November \(7-10,2010,\) where one of the questions on the survey was "Some airports are now using 'full-body' digital x-ray machines to clectronically screen passengers in airport security lines. Do you think these new x-ray machines should or should not be used at airports?" Below is a summary of responses based on party affiliation. \begin{tabular}{llccc} & & \multicolumn{3}{c} { Party Affilation } \\ \cline { 3 - 5 } & & Republican & Democrat & Independent \\ \cline { 2 - 5 } Answer & Should & 264 & 299 & 351 \\ & Should not & 38 & 55 & 77 \\ & Don't know/No answer & 16 & 15 & 22 \\ \cline { 2 - 5 } & Total & 318 & 369 & 450 \end{tabular} (a) Conduct an appropriate hypothesis test evaluating whether there is a difference in the proportion of Republicans and Democrats who think the full- body scans should be applied in airports. Assume that all relevant conditions are met. (b) The conclusion of the test in part (a) may be incorrect, meaning a testing error was made. If an error was made, was it a Type I or a Type II error? Explain.

Short Answer

Expert verified
No significant difference; potential Type II error if incorrect.

Step by step solution

01

Define the Hypotheses

To test whether there is a difference in the proportion of Republicans and Democrats who think full-body scans should be used, we set up our null and alternative hypotheses. Let \( p_R \) be the proportion of Republicans and \( p_D \) the proportion of Democrats who think scans should be used. Null Hypothesis \( (H_0) \): \( p_R = p_D \)Alternative Hypothesis \( (H_a) \): \( p_R eq p_D \)
02

Calculate Sample Proportions

Using the data, calculate the sample proportions for Republicans and Democrats.For Republicans, \( \hat{p}_R = \frac{264}{318} \approx 0.830 \).For Democrats, \( \hat{p}_D = \frac{299}{369} \approx 0.810 \).
03

Calculate the Pooled Proportion

Since we are assuming the null hypothesis is true, we calculate the pooled proportion \( \hat{p} \) from both groups:\[ \hat{p} = \frac{264 + 299}{318 + 369} = \frac{563}{687} \approx 0.820 \].
04

Compute the Standard Error

The standard error for the difference in sample proportions is given by:\[ SE = \sqrt{\hat{p}(1-\hat{p}) \left( \frac{1}{n_R} + \frac{1}{n_D} \right)} \] where \( n_R = 318 \) and \( n_D = 369 \).\[ SE = \sqrt{0.820 \times 0.180 \times \left( \frac{1}{318} + \frac{1}{369} \right)} \approx 0.033 \].
05

Calculate the Test Statistic

Calculate the test statistic for the difference in proportions using:\[ z = \frac{\hat{p}_R - \hat{p}_D}{SE} = \frac{0.830 - 0.810}{0.033} \approx 0.606 \].
06

Determine the p-value

Using the z-value, look up the corresponding p-value in the standard normal distribution table. For a two-tailed test, this z-value \( 0.606 \) corresponds to a p-value of about 0.544.
07

Conclusion of Hypothesis Test

Compare the calculated p-value with the significance level (commonly 0.05). Since 0.544 > 0.05, we fail to reject the null hypothesis. There is no statistically significant difference in the proportions who think the scans should be used between Republicans and Democrats.
08

Identify the Potential Error

Since we failed to reject the null hypothesis when we do not have evidence for a difference, if this decision is incorrect, we would have a Type II error. A Type II error occurs when we fail to reject a false null hypothesis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportions
Proportions play a significant role in statistics, especially when comparing different groups. In hypothesis testing, a proportion represents a part of the whole, providing valuable insight into group opinions or behaviors. For example, calculating proportions helps us understand what share of Republicans or Democrats believe full-body scans should be used at airports.
Proportions are calculated by dividing the number of favorable outcomes by the total number of observations in the group. Here, for Republicans, the proportion is computed by dividing the number of Republicans in favor of scans (264) by the total surveyed Republicans (318):
  • For Republicans, \( \hat{p}_R = \frac{264}{318} \approx 0.830 \).
  • For Democrats, \( \hat{p}_D = \frac{299}{369} \approx 0.810 \).
These proportions form the basis for comparing if there's a significant difference in opinions across political lines.
Null Hypothesis
The null hypothesis, denoted as \( H_0 \), is a fundamental part of hypothesis testing. It serves as the default assumption about a population parameter, suggesting that there is no effect or no difference between groups. In this case, the null hypothesis states there is no difference in the proportion of Republicans and Democrats who support full-body scans.
The goal of hypothesis testing is often to determine whether there is enough evidence to reject the null hypothesis. Here, we define:
  • Null Hypothesis \( (H_0) \): \( p_R = p_D \)
Where \( p_R \) and \( p_D \) are the proportions of Republicans and Democrats, respectively, in favor of using x-ray machines.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_a \), offers a contrasting viewpoint to the null hypothesis. It suggests there is an effect, or there is a difference between groups—a hypothesis that reflects researchers' interests. Here, our alternative hypothesis is that there is a difference between the proportions of Republicans and Democrats who support using full-body scans.
In this exercise, the alternative hypothesis is formulated as:
  • Alternative Hypothesis \( (H_a) \): \( p_R eq p_D \)
This statement indicates we are interested in finding whether the proportions are not equal, exploring any significant variation between the two groups' opinions.
Standard Error
Standard error (SE) measures the variability of a sample statistic as an estimator for a population parameter. It's crucial in hypothesis testing to understand the precision of sample estimates, particularly when comparing proportions. The standard error indicates how much the sample proportion is expected to fluctuate from the actual population proportion.
For the difference in proportions between Republicans and Democrats, the standard error is calculated as:\[SE = \sqrt{\hat{p}(1-\hat{p}) \left( \frac{1}{n_R} + \frac{1}{n_D} \right)}\]where \( \hat{p} \) is the pooled proportion, and \( n_R \) and \( n_D \) are the sample sizes for Republicans and Democrats respectively. Using the given data, the SE is approximately 0.033, providing a measure of how much the estimated difference in proportions may vary by sampling error.
Type I Error
A Type I error arises when the null hypothesis is wrongly rejected, essentially a false positive finding. In hypothesis testing, this means concluding that there is an effect or a difference when, in fact, there isn’t one.
This error is influenced by the significance level. If our significance level is set to 0.05, a Type I error would occur 5% of the time when the null hypothesis is actually true. In the context of the problem, a Type I error would incorrectly suggest that there's a significant difference in opinions between Republicans and Democrats, even when they actually agree.
Type II Error
A Type II error occurs when we fail to reject a null hypothesis that is actually false, meaning a false negative result. This error results in missing a potential finding where a true difference exists but goes undetected.
In the exercise provided, failing to reject the null hypothesis when Republicans and Democrats truly have different opinions on full-body scans represents a Type II error. This error relates directly to the test's power: the higher the study's power, the less likely to commit a Type II error. Unfortunately, more rigorous samples or significant true differences are often needed to minimize Type II errors, meaning statistical tests need careful preparation and execution.
Significance Level
The significance level, usually denoted by \( \alpha \), sets the threshold for deciding whether to reject the null hypothesis. It dictates the probability of making a Type I error, where a common significance level is 0.05. This means a researcher allows a 5% chance of incorrect rejection of the null hypothesis.
In hypothesis testing, if the p-value calculated from the test is less than or equal to the significance level, the null hypothesis is rejected. In this exercise, the p-value was 0.544, which is greater than the typical 0.05 significance level, leading us to fail to reject the null hypothesis. Understanding and setting the significance level is crucial because it balances the risk of errors against practical research considerations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

3.29 Offshore drilling, Part 1. A 2010 survey asked 827 randomly sampled registered voters in California "Do you support? Or do you oppose? Drilling for oil and natural gas off the Coast of California? Or do you not know enough to say?" Below is the distribution of responses, separated based on whether or not the respondent graduated from college. (a) What percent of college graduates and what percent of the non-college graduates in this sample do not know enough to have an opinion on drilling for oil and natural gas off the Coast of California? \begin{tabular}{lcc} & \multicolumn{2}{c} { College Grad } \\ \cline { 2 - 3 } & Yes & No \\ \hline Support & 154 & 132 \\ Oppose & 180 & 126 \\ Do not know & 104 & 131 \\ \hline Total & 438 & 389 \end{tabular} the (b) Conduct a hypothesis test to determine if data provide strong evidence that the proportion of college graduates who do not have an opinion on this issue is different than that of non-college graduates.

HIV in sub-Saharan Africa. In July 2008 the US National Institutes of Health announced that it was stopping a clinical study early because of unexpected results. The study population consisted of HIV-infected women in sub-Saharan Africa who had been given single dose Nevaripine (a treatment for HIV) while giving birth, to prevent transmission of HIV to the infant. The study was a randomized comparison of continued treatment of a woman (after successful childbirth) with Nevaripine vs. Lopinavir, a second drug used to treat HIV. 240 women participated in the study; 120 were randomized to each of the two treatments. Twenty-four weeks after starting the study treatment, each woman was tested to determine if the HIV infection was becoming worse (an outcome called virologic failure). Twenty-six of the 120 women treated with Nevaripine experienced virologic failure, while 10 of the 120 women treated with the other drug experienced virologic failure. (a) Create a two-way table presenting the results of this study. (b) State appropriate hypotheses to test for independence of treatment and virologic failure. (c) Complete the hypothesis test and state an appropriate conclusion. (Reminder: verify any necessary conditions for the test.)

Orange tabbies. Suppose that \(90 \%\) of orange tabby cats are male. Determine if the following statements are true or false, and explain your reasoning. (a) The distribution of sample proportions of random samples of size 30 is left skewed. (b) Using a sample size that is 4 times as large will reduce the standard error of the sample proportion by one-half. (c) The distribution of sample proportions of random samples of size 140 is approximately normal. (d) The distribution of sample proportions of random samples of size 280 is approximately normal.

Prop 19 in California. In a 2010 Survey USA poll, \(70 \%\) of the 119 respondents between the ages of 18 and 34 said they would vote in the 2010 general election for Prop \(19,\) which would change California law to legalize marijuana and allow it to be regulated and taxed. At a \(95 \%\) confidence level, this sample has an \(8 \%\) margin of error. Based on this information, determine if the following statements are true or false, and explain your reasoning." (a) We are \(95 \%\) confident that between \(62 \%\) and \(78 \%\) of the California voters in this sample support Prop \(19 .\) (b) We are \(95 \%\) confident that between \(62 \%\) and \(78 \%\) of all California voters between the ages of 18 and 34 support Prop \(19 .\) (c) If we considered many random samples of 119 California voters between the ages of 18 and 34 , and we calculated \(95 \%\) confidence intervals for each, \(95 \%\) of them will include the true population proportion of Californians who support Prop \(19 .\) (d) In order to decrease the margin of error to \(4 \%\), we would need to quadruple (multiply by 4) the sample size. (e) Based on this confidence interval, there is sufficient evidence to conclude that a majority of California voters between the ages of 18 and 34 support Prop \(19 .\)

Browsing on the mobile device. A 2012 survey of 2,254 American adults indicates that \(17 \%\) of cell phone owners do their browsing on their phone rather than a computer or other device. (a) According to an online article, a report from a mobile research company indicates that 38 percent of Chinese mobile web users only access the internet through their cell phones. " Conduct a hypothesis test to determine if these data provide strong evidence that the proportion of Americans who only use their cell phones to access the internet is different than the Chinese proportion of \(38 \%\) (b) Interpret the p-value in this context. (c) Calculate a \(95 \%\) confidence interval for the proportion of Americans who access the internet on their cell phones, and interpret the interval in this context.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.