/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Orange tabbies. Suppose that \(9... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Orange tabbies. Suppose that \(90 \%\) of orange tabby cats are male. Determine if the following statements are true or false, and explain your reasoning. (a) The distribution of sample proportions of random samples of size 30 is left skewed. (b) Using a sample size that is 4 times as large will reduce the standard error of the sample proportion by one-half. (c) The distribution of sample proportions of random samples of size 140 is approximately normal. (d) The distribution of sample proportions of random samples of size 280 is approximately normal.

Short Answer

Expert verified
False, True, True, True.

Step by step solution

01

Analyze Statement (a)

To determine if the distribution of sample proportions for random samples of size 30 is left-skewed, we must look at the normality of the distribution. For a distribution of sample proportions to be approximately normal, we use the criterion \(np \geq 10\) and \(n(1-p) \geq 10\), where \(p = 0.9\) and \(n = 30\). Calculating these values: \(30 \times 0.9 = 27\) and \(30 \times 0.1 = 3\). Since \(3 < 10\), the sample proportions are skewed and in this case, right-skewed due to the large \(p\). Thus, this statement is false.
02

Evaluate Statement (b)

For a sample size increased by a factor of 4, i.e., from \(n\) to \(4n\), the standard error (SE) of the sample proportion \(\hat{p}\) is reduced. The formula for standard error is \(SE = \sqrt{\frac{p(1-p)}{n}}\). When the sample size is multiplied by 4, the new standard error is \(SE_{new} = \sqrt{\frac{p(1-p)}{4n}} = \frac{SE}{2}\). This reduces the standard error by half, thus making the statement true.
03

Analyze Statement (c)

To assess the normality for a sample size of 140, check if both \(np \geq 10\) and \(n(1-p) \geq 10\). Using \(n = 140\) and \(p = 0.9\), compute:\(140 \times 0.9 = 126\) and \(140 \times 0.1 = 14\). Since both values are \(\geq 10\), the distribution of sample proportions is approximately normal. Therefore, this statement is true.
04

Analyze Statement (d)

Similarly, for \(n = 280\), check the normality condition: \(np \geq 10\) and \(n(1-p) \geq 10\). With \(p = 0.9\), compute \(280 \times 0.9 = 252\) and \(280 \times 0.1 = 28\). Both values \(\geq 10\) confirm the distribution of sample proportions is approximately normal. Thus, this statement is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion is a way to express the fraction of a sample that contextually represents a particular attribute. In any given group, or sample size, it displays the proportion of observations that match a specific category. For example, in the context of the orange tabby cats exercise, if 90% of orange tabby cats are male, then the sample proportion (p) can be defined as 0.9.
The concept of sample proportion is particularly important in statistics because it helps in making inferences about the larger population based on a smaller, manageable sample. When repeatedly taking random samples of a given size, these sample proportions form a distribution. Managing and understanding these distributions leads to more robust statistical conclusions.
This understanding is crucial when determining how often a sample proportion will differ from the actual population proportion—especially in sampling scenarios such as polling or quality control tests.
Normal Distribution
A normal distribution is a key concept in statistics characterized by a bell-shaped curve that is symmetric around the mean. When we talk about sample proportions, we are often checking if their distribution approximates a normal distribution.
In the orange tabby cats context, whether the distribution of sample proportions is normal depends on sample size. The rule of thumb for this approximation is that both the expressions \(np\) and \(n(1-p)\) should be greater than or equal to 10. With the sample proportion given as \(p = 0.9\):
  • For a sample size of 140: \(np = 126\) and \(n(1-p) = 14\), both meet the requirement.
  • For a sample size of 280, \(np = 252\) and \(n(1-p) = 28\), these also meet the requirement.
This means as the sample size increases, the distribution of the sample proportion becomes approximately normal, making it easier to apply further statistical techniques.
Standard Error
The standard error (SE) in statistics measures how much variability there is in a sample statistic, like the sample proportion, compared to the population parameter. It essentially tells us how much the sample proportion \(\hat{p}\) is expected to vary from the actual population proportion \(p\).
The formula to calculate standard error is \(SE = \sqrt{\frac{p(1-p)}{n}}\). This formula shows that the standard error decreases with larger sample sizes. If you multiply your sample size by four, the standard error is halved because you are effectively increasing the accuracy of your estimate. In the exercise, this mathematical property is highlighted to be true, reducing uncertainty and increasing confidence in the estimates.
Understanding standard error is central for hypothesis tests and constructing confidence intervals because it quantifies the precision of the sample proportion compared to the actual population proportion.
Skewness
Skewness is a statistic that tells us about the symmetry—or lack thereof—of the distribution of data. A distribution is skewed if it is not symmetrical. Understanding skewness is crucial when determining whether distribution of our sample proportions fits a certain shape.
In the context of the exercise on orange tabby cats, if the number of sample proportion results is low, the distribution could be skewed. As observed in statement (a), where the sample size of 30 does not hold up the normality condition \(np \geq 10\) and \(n(1-p) \geq 10\), the results show a right-skewed distribution due to the small number of non-male tabbies (3).
A normal distribution has a skewness of zero, indicating that it is perfectly symmetrical. When skewness is not zero, interpretations regarding probabilities and statistics differ, which is why it is always good to check the skewness when analyzing samples.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

True or false, Part I. Determine if the statements below are true or false. For each false statement, suggest an alternative wording to make it a true statement. (a) The chi-square distribution, just like the normal distribution, has two parameters, mean and standard deviation. (b) The chi-square distribution is always right skewed, regardless of the value of the degrees of freedom parameter. (c) The chi-square statistic is always positive. (d) As the degrees of freedom increases, the shape of the chi-square distribution becomes more skewed.

The Daily Show. A 2010 Pew Research foundation poll indicates that among 1,099 college graduates, \(33 \%\) watch The Daily Show. Meanwhile, \(22 \%\) of the 1,110 people with a high school degree but no college degree in the poll watch The Daily Show. A \(95 \%\) confidence interval for ( pcollege grad - Pus ar leas), where \(p\) is the proportion of those who watch The Daily Show, is (0.07,0.15) . Based on this information, determine if the following statements are true or false, and explain your reasoning if you identify the statement as false. (a) At the \(5 \%\) significance level, the data provide convincing evidence of a difference between the proportions of college graduates and those with a high school degree or less who watch The Daily Show. (b) We are \(95 \%\) confident that \(7 \%\) less to \(15 \%\) more college graduates watch The Daily Show than those with a high school degree or less. (c) \(95 \%\) of random samples of 1,099 college graduates and 1,110 people with a high school degree or less will yield differences in sample proportions between \(7 \%\) and \(15 \%\). (d) A \(90 \%\) confidence interval for ( \(p\) college grad \(-\) pus ar lew ) would be wider. (e) A \(95 \%\) confidence interval for (pus ax less \(-p_{\text {college grad }}\) ) is (-0.15,-0.07) .

True or false, Part. II. Determine if the statements below are true or false. For each false statement, suggest an alternative wording to make it a true statement. (a) As the degrees of freedom increases, the mean of the chi-square distribution increases. (b) If you found \(X^{2}=10\) with \(d f=5\) you would fail to reject \(H_{0}\) at the \(5 \%\) significance level. (c) When finding the p-value of a chi-square test, we always shade the tail areas in both tails. (d) As the degrees of freedom increases, the variability of the chi-square distribution decreases.

Young Americans, Part. II. About \(25 \%\) of young Americans have delayed starting a family due to the continued economic slump. Determine if the following statements are true or false, and explain your reasoning. (a) The distribution of sample proportions of young Americans who have delayed starting a family due to the continued economic slump in random samples of size 12 is right skewed. (b) In order for the the distribution of sample proportions of young Americans who have delayed starting a family due to the continued economic slump to be approximately normal, we need random samples where the sample size is at least 40 . (c) A random sample of 50 young Americans where \(20 \%\) have delayed starting a family due to the continued economic slump would be considered unusual. (d) A random sample of 150 young Americans where \(20 \%\) have delayed starting a family due to the continued economic shmp would be considered unusual. (e) Tripling the sample size will reduce the standard error of the sample proportion by one-third.

Diabetes and unemployment. A 2012 Gallup poll surveyed Americans about their employment status and whether or not they have diabetes. The survey results indicate that \(1.5 \%\) of the 47,774 employed (full or part time) and \(2.5 \%\) of the 5,855 unemployed \(18-29\) year olds have diabetes. (a) Create a two-way table presenting the results of this study. (b) State appropriate hypotheses to test for independence of incidence of diabetes and employment status. (c) The sample difference is about \(1 \%\). If we completed the hypothesis test, we would find that the p-value is very small (about 0 ), meaning the difference is statistically significant. Use this result to explain the difference between statistically significant and practically significant findings.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.