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Browsing on the mobile device. A 2012 survey of 2,254 American adults indicates that \(17 \%\) of cell phone owners do their browsing on their phone rather than a computer or other device. (a) According to an online article, a report from a mobile research company indicates that 38 percent of Chinese mobile web users only access the internet through their cell phones. " Conduct a hypothesis test to determine if these data provide strong evidence that the proportion of Americans who only use their cell phones to access the internet is different than the Chinese proportion of \(38 \%\) (b) Interpret the p-value in this context. (c) Calculate a \(95 \%\) confidence interval for the proportion of Americans who access the internet on their cell phones, and interpret the interval in this context.

Short Answer

Expert verified
The hypothesis test shows strong evidence that the American and Chinese proportions differ. The p-value interpretation reveals the likelihood of extreme observations under the null hypothesis. The 95% confidence interval for Americans is (0.153, 0.187).

Step by step solution

01

Define Hypotheses

To test if the proportion of Americans who only use their cell phones to access the internet is different from the Chinese proportion, set up the null and alternative hypotheses. Let \( p \) be the proportion of Americans. Then:\[ H_0: p = 0.38 \] \[ H_a: p eq 0.38 \] This is a two-tailed test since we are checking for a difference, not a specific direction of effect.
02

Calculate the Test Statistic

Use the sample proportion from the survey, which is \( \hat{p} = 0.17 \). The sample size \( n = 2254 \). Compute the standard error (SE) using:\[ SE = \sqrt{\frac{p_0 (1 - p_0)}{n}} \] where \( p_0 = 0.38 \). Then, calculate the Z-score:\[ Z = \frac{\hat{p} - p_0}{SE} \]
03

Find the P-value

Using the Z-score obtained from Step 2, determine the p-value. Use standard normal probability tables or a calculator to find the probability of observing a Z as extreme as, or more extreme than, our calculated Z, under the null hypothesis.
04

Make a Decision

Compare the p-value with the significance level (usually \( \alpha = 0.05 \)). If the p-value \( < \alpha \), reject the null hypothesis; otherwise, fail to reject it. This will determine if there's strong evidence against the null hypothesis.
05

Interpret the P-value

The p-value measures the probability of observing data as extreme as the evidence against the null hypothesis, assuming the null hypothesis is true. A small p-value indicates strong evidence against the null hypothesis.
06

Calculate the Confidence Interval

To find the \(95 \% \) confidence interval for the American proportion, use the formula for the confidence interval for a proportion:\[ \hat{p} \pm Z^* \times \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \] where \( Z^* \) is the critical Z-value for \(95\%\) confidence (approximately 1.96), \( \hat{p} = 0.17 \), and \( n = 2254 \).
07

Interpret the Confidence Interval

The confidence interval provides a range where we are \(95 \%\) confident the true proportion of Americans who access the internet via cell phones lies. If this interval does not include the Chinese proportion, it suggests a notable difference.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
When analyzing survey results, a confidence interval offers a way to estimate the range in which the true parameter is likely to fall, based on a sample statistic. In our case, we want to create a confidence interval for the proportion of Americans who use their phones as the only means to browse the internet. This interval will give us insights into how this behavior might look in the total population of American adults.

To calculate the confidence interval, we use the sample proportion (\( \hat{p} = 0.17 \)) and the number of survey respondents (\( n = 2254 \)). The formula for a confidence interval is:
  • \( \hat{p} \pm Z^* \times \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \)
Here, \( Z^* \) is the Z-value that corresponds to our desired confidence level (95% in this case), which is about 1.96.

This calculation involves multiplying \( Z^* \) by the standard error of the proportion, which reflects the accuracy of our sample's proportion as an estimate of the actual proportion in the entire population.

Once calculated, the confidence interval provides a range in which we can be 95% certain the real proportion of Americans using phones exclusively to browse the internet lies. If this interval doesn't contain the hypothesized 38% from the Chinese data, it suggests a meaningful difference in browsing habits between the two populations.
Proportion Testing
Proportion testing helps us analyze whether the sample proportion of a particular characteristic significantly deviates from a known standard or hypothesized value. In this scenario, we're testing if the proportion of Americans who primarily use their phones to access the web differs from the stated Chinese proportion of 38%.

We begin by setting up hypotheses:
  • Null hypothesis (\( H_0 \)): The proportion of Americans using phones is equal to 38% (\( p = 0.38 \)).
  • Alternative hypothesis (\( H_a \)): The proportion is different (\( p eq 0.38 \)).
By employing a two-tailed test, we check for any significant difference, whether higher or lower than the Chinese proportion. The next step is to calculate the test statistic, a Z-score, which quantifies the number of standard deviations the observed proportion (17%) is from the hypothesized 38%.

This Z-score helps in determining the p-value, which represents the probability of observing such a difference in the sample data by random chance, assuming the null hypothesis is correct. By comparing this p-value against a predetermined significance level, typically 0.05, we decide whether to reject or fail to reject the null hypothesis. A low p-value suggests the sample data provides strong evidence that the true proportion of web usage via phones among Americans is indeed different from 38%.
Standard Error
Standard error (SE) is a pivotal concept in hypothesis testing and confidence intervals. It measures the variability, or "spread," of a sample statistic, such as a mean or proportion from its true population parameter. Essentially, it helps us gauge the precision of our sample estimate.

In this exercise, the standard error is crucial in calculating both the test statistic (in proportion testing) and the confidence interval. The formula for standard error of a proportion is:
  • \( SE = \sqrt{\frac{p_0 (1 - p_0)}{n}} \)
Here, \( p_0 \) is the hypothesized population proportion (38% in our scenario), and \( n \) is the sample size, 2254.

The SE helps to understand how much variability one might expect in repeated sampling. A smaller SE suggests that the sample mean is a more accurate reflection of the population mean, indicating less random error.

When using SE to determine the Z-score or during confidence interval calculations, it introduces the idea of uncertainty and statistical variation into our estimates. This ensures we account for the sample not perfectly representing the entire population, allowing us to make more grounded conclusions based on our data. By understanding SE, students can better grasp the concepts of sample reliability and the role of probability in statistical analysis.

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