/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Life rating in Greece. Greece ha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Life rating in Greece. Greece has faced a severe economic crisis since the end of \(2009 .\) A Gallup poll surveyed 1,000 randomly sampled Greeks in 2011 and found that \(25 \%\) of them said they would rate their lives poorly enough to be considered "suffering". (a) Describe the population parameter of interest. What is the value of the point estimate of this parameter? (b) Check if the conditions required for constructing a confidence interval based on these data are met. (c) Construct a \(95 \%\) confidence interval for the proportion of Greeks who are "suffering". (d) Without doing any calculations, describe what would happen to the confidence interval if we decided to use a higher confidence level. (e) Without doing any calculations, describe what would happen to the confidence interval if we used a larger sample.

Short Answer

Expert verified
(a) True proportion of 'suffering' Greeks; point estimate is 0.25. (b) Conditions satisfied. (c) CI: (0.2232, 0.2768). (d) Higher confidence level widens CI. (e) Larger sample narrows CI.

Step by step solution

01

Identify the Population Parameter

The population parameter of interest is the true proportion of Greeks in 2011 who rate their lives poorly enough to be considered 'suffering'. This is what we aim to estimate using the sample data.
02

Point Estimate

The point estimate for the population proportion, based on the sample, is the sample proportion. With 1,000 Greeks surveyed, 25% said they were 'suffering'. Hence, the point estimate is \(\hat{p} = 0.25\).
03

Check Conditions for Confidence Interval

The conditions for constructing a confidence interval for a proportion are: 1. Random Sample: The sample of 1,000 Greeks is a random sample.2. Large Enough Sample: The sample size is large enough if \(np \geq 10\) and \(n(1-p) \geq 10\). Here, \(np = 1,000 \times 0.25 = 250\) and \(n(1-p) = 1,000 \times 0.75 = 750\), both greater than 10.Both conditions are satisfied, so we can proceed.
04

Construct Confidence Interval

To construct a 95% confidence interval for the proportion:1. Find the standard error: \(SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.25 \times 0.75}{1,000}} = 0.0137\).2. Find the critical value for a 95% confidence level (\(z\)-score ≈ 1.96).3. Compute the margin of error: \(ME = 1.96 \times 0.0137 = 0.0268\).4. The confidence interval is: \(\hat{p} \pm ME = 0.25 \pm 0.0268 = (0.2232, 0.2768)\).
05

Effect of Higher Confidence Level

Increasing the confidence level would require a larger critical value, which increases the margin of error. Therefore, the confidence interval would be wider, indicating more uncertainty in the estimate.
06

Effect of Larger Sample

Using a larger sample reduces the standard error because \(SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\). This leads to a smaller margin of error, thus resulting in a narrower confidence interval, providing a more precise estimate of the population proportion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Parameter
In the context of statistical analysis, a population parameter is a value that represents a characteristic of an entire population. It's often unknown and is what researchers aim to estimate based on sample data. Here, the population parameter of interest is the true proportion of Greeks in 2011 who rate their lives as 'suffering' during the economic crisis.

This parameter gives us a picture of the overall well-being of Greeks at the time and guides social scientists to understand and address issues related to the crisis. Estimating this parameter accurately helps in making data-informed decisions and understanding the societal impact of economic conditions.
Point Estimate
A point estimate provides a single value estimate of a population parameter. It is calculated from sample data and serves as the best guess of the true population parameter. In the given scenario, the point estimate is derived from the Gallup poll where 1,000 Greeks were surveyed, and 25% reported 'suffering'.

The calculation is straightforward: the point estimate \( \hat{p} = 0.25 \). This is based on the sample proportion, meaning that approximately 25% of the sampled Greeks considered themselves to be suffering.
  • This point estimate is used as a basis to construct confidence intervals, offering insights with a quantifiable likelihood.
It represents the center of a confidence interval, which provides a range of values for better estimating the true population parameter.
Gallup Poll
The Gallup Poll is a reputable survey-based research method commonly used to assess public opinion on various social issues, including economic conditions, health, and quality of life. It helps to gauge the sentiment of a population through random samples and rigorous methods.
  • Gallup ensures a representative sample by randomly selecting individuals, which increases the validity of the survey results.
  • Results provide a snapshot of how certain situations, like the economic crisis in Greece, impact citizens.

In this exercise, the Gallup Poll was central to gathering data from Greek citizens, allowing researchers to estimate the level of suffering during a specific period. Such polls are crucial for providing policy-makers with the necessary insights to craft informed strategies and interventions aimed at alleviating such societal challenges.
Standard Error
The standard error (SE) is a statistic that measures how much the sample proportion is expected to fluctuate from the true population proportion. It's a key component in determining how precise our point estimate is. The smaller the standard error, the more reliable the point estimate becomes.

For this Gallup poll scenario, the formula used is \( SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \), where \( \hat{p} \) is the sample proportion, and \( n \) is the sample size. Here, the SE was calculated to be approximately 0.0137, indicating how much the sample proportion might differ from the actual population proportion.
  • A lower SE suggests less variability in our estimates, leading to narrower confidence intervals, thus providing more precise estimates about the population.
  • If we had a larger sample size, the SE would decrease, further enhancing the accuracy of our predictions.
Understanding and calculating SE is essential for constructing confidence intervals and assessing the accuracy of estimates.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Prenatal vitamins and Autism. Researchers studying the link between prenatal vitamin use and autism surveyed the mothers of a random sample of children aged \(24-60\) months with autism and conducted another separate random sample for children with typical development. The table below shows the number of mothers in each group who did and did not use prenatal vitamins during the three months before pregnancy (periconceptional period). 40 \begin{tabular}{llccc} & \multicolumn{4}{c} { Autism } \\ \cline { 3 - 4 } & & Autism Typical development & Total \\ \cline { 2 - 5 } Periconceptional & No vitamin & 111 & 70 & 181 \\ prenatal vitamin & Vitamin & 143 & 159 & 302 \\ \cline { 2 - 5 } & Total & 254 & 229 & 483 \end{tabular} (a) State appropriate hypotheses to test for independence of use of prenatal vitamins during the three months before pregnancy and autism. (b) Complete the hypothesis test and state an appropriate conclusion. (Reminder: verify any necessary conditions for the test.) (c) A New York Times article reporting on this study was titled "Prenatal Vitamins May Ward Off Autism", Do you find the title of this article to be appropriate? Explain your answer. Additionally, propose an alternative title.

Vegetarian college students. Suppose that \(8 \%\) of college students are vegetarians. Determine if the following statements are true or false, and explain your reasoning. (a) The distribution of the sample proportions of vegetarians in random samples of size 60 is approximately normal since \(n \geq 30\). (b) The distribution of the sample proportions of vegetarian college students in random samples of size 50 is right skewed. (c) A random sample of 125 college students where \(12 \%\) are vegetarians would be considered unusual. (d) A random sample of 250 college students where \(12 \%\) are vegetarians would be considered unusual. (e) The standard error would be reduced by one-half if we increased the sample size from 125 to 250 .

Sleep deprivation, CA vs. OR, Part I. According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is \(8.0 \%\), while this proportion is \(8.8 \%\) for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a \(95 \%\) confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data. \(^{44}\)

Gender and color preference. A 2001 study asked 1,924 male and 3,666 female undergraduate college students their favorite color. A \(95 \%\) confidence interval for the difference between the proportions of males and females whose favorite color is black ( \(p_{\text {male }}-p\) female \()\) was calculated to be (0.02,0.06) . Based on this information, determine if the following statements are true or false, and explain your reasoning for each statement you identify as false. 2 (a) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) lower to \(6 \%\) higher than the true proportion of females whose favorite color is black. (b) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) to \(6 \%\) higher than the true proportion of females whose favorite color is black. (c) \(95 \%\) of random samples will produce \(95 \%\) confidence intervals that include the true difference between the population proportions of males and females whose favorite color is black. (d) We can conclude that there is a significant difference between the proportions of males and females whose favorite color is black and that the difference between the two sample proportions is too large to plausibly be due to chance. (e) The \(95 \%\) confidence interval for \(\left(p_{\text {female }}-p_{\text {male }}\right)\) cannot be calculated with only the information given in this exercise.

Prop 19 in California. In a 2010 Survey USA poll, \(70 \%\) of the 119 respondents between the ages of 18 and 34 said they would vote in the 2010 general election for Prop \(19,\) which would change California law to legalize marijuana and allow it to be regulated and taxed. At a \(95 \%\) confidence level, this sample has an \(8 \%\) margin of error. Based on this information, determine if the following statements are true or false, and explain your reasoning." (a) We are \(95 \%\) confident that between \(62 \%\) and \(78 \%\) of the California voters in this sample support Prop \(19 .\) (b) We are \(95 \%\) confident that between \(62 \%\) and \(78 \%\) of all California voters between the ages of 18 and 34 support Prop \(19 .\) (c) If we considered many random samples of 119 California voters between the ages of 18 and 34 , and we calculated \(95 \%\) confidence intervals for each, \(95 \%\) of them will include the true population proportion of Californians who support Prop \(19 .\) (d) In order to decrease the margin of error to \(4 \%\), we would need to quadruple (multiply by 4) the sample size. (e) Based on this confidence interval, there is sufficient evidence to conclude that a majority of California voters between the ages of 18 and 34 support Prop \(19 .\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.