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Privacy on Facebook. A 2011 survey asked 806 randomly sampled adult Facebook users about their Facebook privacy settings. One of the questions on the survey was, "Do you know how to adjust your Facebook privacy settings to control what people can and cannot see?" The responses are cross-tabulated based on gender. \begin{tabular}{llccc} & & \multicolumn{2}{c} { Gender } & \\ \cline { 3 - 4 } & & Male & Female & Total \\ \cline { 2 - 5 } Response & Yes & 288 & 378 & 666 \\ & No & 61 & 62 & 123 \\ & Not sure & 10 & 7 & 17 \\ \cline { 2 - 5 } & Total & 359 & 447 & 806 \end{tabular} (a) State appropriate hypotheses to test for independence of gender and whether or not Facebook users know how to adjust their privacy settings. (b) Verify any necessary conditions for the test and determine whether or not a chi-square test. can be completed.

Short Answer

Expert verified
The hypotheses are set, and the chi-square test conditions are met, so you can proceed with the test.

Step by step solution

01

Define the Hypotheses

We need to establish the null hypothesis and the alternative hypothesis for the test of independence. The null hypothesis (\( H_0 \)) states that gender and knowing how to adjust privacy settings are independent, while the alternative hypothesis (\( H_a \)) states that they are dependent:- \( H_0 \): Gender and knowledge of adjusting privacy settings are independent.- \( H_a \): Gender and knowledge of adjusting privacy settings are not independent.
02

Calculate Expected Frequencies

Using the totals of each row and column, calculate the expected frequency for each cell under the assumption that \( H_0 \) is true using the formula: \( E_{ij} = \frac{(Row \, Total_i) imes (Column \, Total_j)}{Grand \, Total} \).For example, for the 'Yes' response by males, the expected frequency is calculated as:\[E_{Yes, Male} = \frac{(359) \times (666)}{806} \approx 296.75\]Calculate similar expected frequencies for all other cells:
03

Verify Conditions for Chi-Square Test

For a chi-square test to be valid, expected frequencies should be at least 5 in each cell. Calculate the remaining expected frequencies:- \( E_{Yes, Female} \approx 369.25 \)- \( E_{No, Male} \approx 54.82 \)- \( E_{No, Female} \approx 68.18 \)- \( E_{Not \, sure, Male} \approx 8.43 \)- \( E_{Not \, sure, Female} \approx 8.57 \)All expected frequencies are greater than 5, so the chi-square test is appropriate.
04

Conclusion

Since all the conditions for the chi-square test are met, we can proceed with conducting the chi-square test for independence between gender and knowledge of privacy settings. The test would involve calculating the test statistic and comparing it to a critical value or assessing the p-value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence Testing
Independence testing is a way to see if two variables are related or not in a statistical sense. Imagine you're looking at gender and the ability of Facebook users to adjust their privacy settings, as in the survey. Here, we're testing whether these two things, gender and privacy adjustment knowledge, depend on each other. If they are independent, knowing one tells you nothing about the other.

We use the null hypothesis, noted as \( H_0 \), to state they are independent. If our data says otherwise, we reject this hypothesis, supporting the alternative hypothesis \( H_a \) that they are not independent.

To determine whether gender and privacy adjustment knowledge are indeed independent, we often use a chi-square test. This test compares what we expect to see if the variables are independent versus what we actually see in our data.
Expected Frequencies
Expected frequencies are the numbers we would anticipate if there is no relationship between the variables, in this case, gender and the ability to adjust privacy settings. It's like guessing how many people would respond "Yes," "No," or "Not sure" under the idea that gender doesn't affect their choice.

We calculate these using \[ E_{ij} = \frac{(\text{Row Total}_i) \times (\text{Column Total}_j)}{\text{Grand Total}} \]where each cell in the table has its own expected value. For instance, for males answering "Yes," given their total and the total of "Yes" responses, we use this formula to find out the expected number. This helps in setting a benchmark to measure our observed data against.

By comparing each expected frequency with the actual one, we can see where the data differs from what we'd expect if the two variables were independent.
Survey Data Analysis
Survey data analysis involves examining collected survey responses to make sense of what they've told us. In the Facebook privacy settings survey, cross-tabulating the responses by gender helps us understand at a glance how different genders feel about their ability to adjust privacy settings.

This form of data analysis helps in summarizing the entire survey into meaningful insights. We not only count responses but also see patterns and relationships, like perhaps more females than males knowing how to change settings, or if both have similar percentages.

By exploring the data in this structured format, we derive insights which can drive further decisions or hypotheses about the population, leading to effective research outcomes.
Hypothesis Testing
Hypothesis testing is at the heart of deciding if your data supports or contradicts your assumptions. In our scenario, we set up two competing hypotheses about gender and privacy knowledge. \( H_0 \) posits that gender does not influence knowledge, whereas \( H_a \) suggests it does.

Once we have our hypotheses, we use statistical tests like the chi-square to test them. The chi-square test compares observed frequencies from our survey data to the expected frequencies if \( H_0 \) is true.

We conclude by either rejecting \( H_0 \), suggesting a significant relationship between the variables, or failing to reject it, indicating no evidence against independence. This systematic method enables us to make evidence-based decisions about our presumptions and validate our analysis outcomes.

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Most popular questions from this chapter

Life rating in Greece. Greece has faced a severe economic crisis since the end of \(2009 .\) A Gallup poll surveyed 1,000 randomly sampled Greeks in 2011 and found that \(25 \%\) of them said they would rate their lives poorly enough to be considered "suffering". (a) Describe the population parameter of interest. What is the value of the point estimate of this parameter? (b) Check if the conditions required for constructing a confidence interval based on these data are met. (c) Construct a \(95 \%\) confidence interval for the proportion of Greeks who are "suffering". (d) Without doing any calculations, describe what would happen to the confidence interval if we decided to use a higher confidence level. (e) Without doing any calculations, describe what would happen to the confidence interval if we used a larger sample.

Shipping holiday gifts. A December 2010 survey asked 500 randomly sampled Los Angeles residents which shipping carrier they prefer to use for shipping holiday gifts. The table below shows the distribution of responses by age group as well as the expected counts for each cell (shown in parentheses). Method \begin{tabular}{l|cc|cc|cc|c} & \multicolumn{6}{|c|} { Age } & \\ \cline { 2 - 5 } & \multicolumn{2}{|c|} {\(18-34\)} & \multicolumn{2}{|c|} {\(35-54\)} & \multicolumn{2}{|c|} {\(55+\)} & Total \\ \hline USPS & 72 & \((\mathrm{~B} 1)\) & 97 & (102) & 76 & (62) & 245 \\ UPS & 52 & (83) & 76 & \((6 \mathrm{~b})\) & 34 & (41) & 162 \\ FedEx & 31 & (21) & 24 & (27) & 9 & (16) & 64 \\ Something else & 7 & (5) & 6 & (7) & 3 & (4) & 16 \\ Not sure & 3 & (5) & 6 & (5) & 4 & (3) & 13 \\ \hline Total & \multicolumn{2}{|c|} {165} & \multicolumn{2}{|c|} {209} & \multicolumn{2}{|c|} {126} & 500 \end{tabular} (a) State the null and alternative hypotheses for testing for independence of age and preferred shipping method for holiday gifts among Los Angeles residents. (b) Are the conditions for inference using a chi-square test satisfied?

Fireworks on July \(4^{\text {th }}\). In late June 2012, Survey USA published results of a survey stating that \(56 \%\) of the 600 randomly sampled Kansas residents planned to set off fireworks on July \(4^{t h}\). Determine the margin of error for the \(56 \%\) point estimate using a \(95 \%\) confidence level.

Offshore drilling, Part II. Results of a poll evaluating support for drilling for oil and natural gas off the coast of California were introduced in Exercise \(3.29 .\) \begin{tabular}{lcc} & \multicolumn{2}{c} { College Grad } \\ \cline { 2 - 3 } & Yes & No \\ \hline Support & 154 & 132 \\ Oppose & 180 & 126 \\ Do not know & 104 & 131 \\ \hline Total & 438 & 389 \end{tabular} (a) What percent of college graduates and what percent of the non-college graduates in this sample support drilling for oil and natural gas off the Coast of California? (b) Conduet a hypothesis test to determine if the data provide strong evidence that the proportion of college graduates who support off-shore drilling in California is different than that of noncollege graduates.

Gender and color preference. A 2001 study asked 1,924 male and 3,666 female undergraduate college students their favorite color. A \(95 \%\) confidence interval for the difference between the proportions of males and females whose favorite color is black ( \(p_{\text {male }}-p\) female \()\) was calculated to be (0.02,0.06) . Based on this information, determine if the following statements are true or false, and explain your reasoning for each statement you identify as false. 2 (a) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) lower to \(6 \%\) higher than the true proportion of females whose favorite color is black. (b) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) to \(6 \%\) higher than the true proportion of females whose favorite color is black. (c) \(95 \%\) of random samples will produce \(95 \%\) confidence intervals that include the true difference between the population proportions of males and females whose favorite color is black. (d) We can conclude that there is a significant difference between the proportions of males and females whose favorite color is black and that the difference between the two sample proportions is too large to plausibly be due to chance. (e) The \(95 \%\) confidence interval for \(\left(p_{\text {female }}-p_{\text {male }}\right)\) cannot be calculated with only the information given in this exercise.

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