/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Sleep deprived transportation wo... [FREE SOLUTION] | 91Ó°ÊÓ

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Sleep deprived transportation workers. The National Sleep Foundation conducted a survey on the sleep habits of randomly sampled transportation workers and a control sample of non-transportation workers. The results of the survey are shown below. \begin{tabular}{lccccc} & \multicolumn{4}{c} { Transportation Professionals } \\ \cline { 3 - 6 } & & & Truck & Train & Bux/1axi/Limo \\ & Control & Pilots & Drivers & Operators & Drivers \\ \hline Less than 6 hours of sleep & 35 & 19 & 35 & 29 & 21 \\ 6 to 8 hours of sleep & 193 & 132 & 117 & 119 & 131 \\ More than 8 hours & 64 & 51 & 51 & 32 & 58 \\ \hline Total & 292 & 202 & 203 & 180 & 210 \end{tabular} Conduct a hypothesis test to evaluate if these data provide evidence of a difference between the proportions of truck drivers and non-transportation workers (the control group) who get less than 6 hours of sleep per day, i.e. are considered sleep deprived.

Short Answer

Expert verified
There is no significant evidence to claim a difference in sleep deprivation between truck drivers and the control group.

Step by step solution

01

Define Hypotheses

First, we need to set up our null and alternative hypotheses. The null hypothesis (\( H_0 \)) claims that there is no difference between the proportions of truck drivers and the control group who get less than 6 hours of sleep. The alternative hypothesis (\( H_a \)) contends that these proportions are different. Mathematically, you express this as:\(H_0: p_{\text{truck}} = p_{\text{control}} \H_a: p_{\text{truck}} eq p_{\text{control}}\)
02

Calculate Sample Proportions

Calculate the proportions of truck drivers and control group that get less than 6 hours of sleep. For truck drivers, \( p_{\text{truck}} = \frac{35}{203} \approx 0.172 \), and for the control group, \( p_{\text{control}} = \frac{35}{292} \approx 0.120 \).
03

Compute the Standard Error

The standard error (SE) for the difference in two proportions is calculated using:\[ SE = \sqrt{\frac{p_{\text{combined}} (1 - p_{\text{combined}})}{n_{\text{truck}}} + \frac{p_{\text{combined}} (1 - p_{\text{combined}})}{n_{\text{control}}}} \]where \( p_{\text{combined}} = \frac{35+35}{203+292} = \frac{70}{495} \approx 0.141 \). Thus:\[ SE \approx \sqrt{\frac{0.141 \times 0.859}{203} + \frac{0.141 \times 0.859}{292}} \approx 0.028 \].
04

Calculate the Z-score

The Z-score is obtained by \[ Z = \frac{(p_{\text{truck}} - p_{\text{control}})}{SE} \]Substitute the values:\[ Z = \frac{0.172 - 0.120}{0.028} \approx 1.86 \].
05

Determine the Significance Level and Make Decision

Typically, we use a significance level \( \alpha = 0.05 \). The critical Z-value for a two-tailed test at \( 95\% \) confidence level is approximately \( \pm 1.96 \). Since the computed Z-score (1.86) is less than 1.96, we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions: Understanding the Basics
Sample proportions are a fundamental part of hypothesis testing. A sample proportion is simply the fraction or percentage of subjects in a sample that possess a certain characteristic. In the given problem, we are examining the proportion of individuals who get less than 6 hours of sleep in two different groups: truck drivers and a control group of non-transportation workers. To find the sample proportion for truck drivers, we calculate it as follows:
  • Number of truck drivers with less than 6 hours of sleep: 35
  • Total number of truck drivers surveyed: 203
The sample proportion for truck drivers is calculated as: \[ p_{\text{truck}} = \frac{35}{203} \approx 0.172 \]Similarly, for the control group, the sample proportion is: \[ p_{\text{control}} = \frac{35}{292} \approx 0.120 \]These simple calculations form the basis of comparing proportions between two groups.
Standard Error: Measuring Sample Variability
The standard error (SE) is a measure of the variability or spread of sample proportion estimates from different samples. It's crucial in hypothesis testing because it tells us how much variability we can expect in the sample proportions if we repeated our survey multiple times. In our transportation worker example, calculating the SE for the difference in proportions helps gauge how much the estimated proportions might differ purely due to chance.
To calculate the standard error for the difference between two sample proportions, use:\[ SE = \sqrt{\frac{p_{\text{combined}} (1 - p_{\text{combined}})}{n_{\text{truck}}} + \frac{p_{\text{combined}} (1 - p_{\text{combined}})}{n_{\text{control}}}} \]Here, \( p_{\text{combined}} \) is the combined proportion:\[ p_{\text{combined}} = \frac{35+35}{203+292} = \frac{70}{495} \approx 0.141 \]Detecting changes in this combined proportion is essential for evaluating the results. Using this, we find:\[ SE \approx \sqrt{\frac{0.141 \times 0.859}{203} + \frac{0.141 \times 0.859}{292}} \approx 0.028 \]This tells us how much the proportion estimates are expected to vary due to random sampling.
Z-score: Comparing Observed Data With Expectation
The Z-score is a statistical measure that shows how far away a data point is from the mean of a population in standard deviation units. It's used in hypothesis testing to determine whether the difference between sample proportions is significant. Here, we want to know if the observed difference in the proportion of sleep-deprived individuals between truck drivers and the control group is statistically significant.
To calculate the Z-score, we use:\[ Z = \frac{(p_{\text{truck}} - p_{\text{control}})}{SE} \]Substituting the relevant values, we find:\[ Z = \frac{0.172 - 0.120}{0.028} \approx 1.86 \]The Z-score of 1.86 helps us compare the observed difference against random variation. This score will then be used to make a decision about our hypotheses.
Significance Level: Making a Decision
The significance level, often denoted by \( \alpha \), is a threshold set by the researcher used to judge the statistical evidence against the null hypothesis. A common significance level is 0.05, meaning there's a 5% risk of concluding that a difference exists when there is none. In hypothesis testing, once we calculate the Z-score, we compare it to a critical value derived from the significance level.
For a two-tailed test with \( \alpha = 0.05 \), the critical Z-value is approximately \( \pm 1.96 \). The computed Z-score of 1.86 is less than the critical value of 1.96. This means the observed difference in proportions isn't large enough to warrant rejecting the null hypothesis.
  • If the Z-score is greater than 1.96 or less than -1.96, we reject the null hypothesis.
  • If it falls between -1.96 and 1.96, we fail to reject it.
In this case, since the Z-score does not exceed the critical value, we conclude there is not enough evidence to claim a significant difference in sleep deprivation between the two groups.

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Most popular questions from this chapter

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