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HIV in sub-Saharan Africa. In July 2008 the US National Institutes of Health announced that it was stopping a clinical study early because of unexpected results. The study population consisted of HIV-infected women in sub-Saharan Africa who had been given single dose Nevaripine (a treatment for HIV) while giving birth, to prevent transmission of HIV to the infant. The study was a randomized comparison of continued treatment of a woman (after successful childbirth) with Nevaripine vs. Lopinavir, a second drug used to treat HIV. 240 women participated in the study; 120 were randomized to each of the two treatments. Twenty-four weeks after starting the study treatment, each woman was tested to determine if the HIV infection was becoming worse (an outcome called virologic failure). Twenty-six of the 120 women treated with Nevaripine experienced virologic failure, while 10 of the 120 women treated with the other drug experienced virologic failure. (a) Create a two-way table presenting the results of this study. (b) State appropriate hypotheses to test for independence of treatment and virologic failure. (c) Complete the hypothesis test and state an appropriate conclusion. (Reminder: verify any necessary conditions for the test.)

Short Answer

Expert verified
There is a significant relationship between treatment type and virologic failure.

Step by step solution

01

Organize Data into Two-Way Table

To create a two-way table, we need to organize the data into rows and columns. The two treatments are Nevaripine and Lopinavir. The outcomes are 'Virologic Failure' and 'No Virologic Failure'. So, the table will have the following format: | | Virologic Failure | No Virologic Failure | Total | |----------------|-------------------|----------------------|-------| | Nevaripine | 26 | 94 | 120 | | Lopinavir | 10 | 110 | 120 | | Total | 36 | 204 | 240 | Here, 26 women on Nevaripine and 10 women on Lopinavir experienced virologic failure. The total number of women is 240, with 36 experiencing virologic failure.
02

State Hypotheses for Independence

The null hypothesis (\(H_0\)) is that there is no relationship between the type of treatment and the outcome of virologic failure, meaning the treatment and outcome are independent. The alternative hypothesis (\(H_a\)) is that there is a relationship, meaning the type of treatment affects the outcome of virologic failure.\[H_0: \text{Treatment and virologic failure are independent.} \H_a: \text{Treatment and virologic failure are not independent.}\]
03

Calculate Expected Frequencies

To perform a chi-square test, calculate the expected frequencies for each cell under the assumption of independence. The expected frequency for each cell is given by \(E = \frac{(\text{Row Total}) \times (\text{Column Total})}{\text{Grand Total}}\).For Nevaripine with virologic failure:\[E_{Nevaripine, Failure} = \frac{120 \times 36}{240} = 18\]For Nevaripine with no virologic failure:\[E_{Nevaripine, No Failure} = \frac{120 \times 204}{240} = 102\]For Lopinavir with virologic failure:\[E_{Lopinavir, Failure} = \frac{120 \times 36}{240} = 18\]For Lopinavir with no virologic failure:\[E_{Lopinavir, No Failure} = \frac{120 \times 204}{240} = 102\]
04

Perform Chi-Square Test for Independence

The chi-square statistic is calculated using:\[\chi^2 = \sum \frac{(O - E)^2}{E}\]where \(O\) is the observed frequency and \(E\) is the expected frequency.\[\chi^2 = \frac{(26 - 18)^2}{18} + \frac{(94 - 102)^2}{102} + \frac{(10 - 18)^2}{18} + \frac{(110 - 102)^2}{102} \]\[\chi^2 = \frac{64}{18} + \frac{64}{102} + \frac{64}{18} + \frac{64}{102} \]\[\chi^2 = 3.56 + 0.63 + 3.56 + 0.63 = 8.38\]With 1 degree of freedom, compare this to the critical value from the chi-square distribution table or calculate the p-value.
05

Draw Conclusion

For a significance level of 0.05, the critical value of chi-square with 1 degree of freedom is approximately 3.84. Since our calculated \(\chi^2\) of 8.38 is greater than 3.84, we reject the null hypothesis. This suggests a significant relationship between the type of treatment and virologic failure. Therefore, the treatment seems to affect virologic failure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a fundamental method used in statistics to determine if there is enough evidence to reject a hypothesis about how two or more groups are related. This method is particularly useful when analyzing studies or experiments where researchers want to understand the relationship between variables.

In this exercise, hypothesis testing is used to evaluate whether the type of treatment (Nevaripine vs. Lopinavir) has any effect on virologic failure in HIV-infected women. We start by establishing two hypotheses: the null hypothesis ( $H_0$ ) and the alternative hypothesis ( $H_a$ ).

  • The null hypothesis ( $H_0$ ) posits that there is no association between treatment type and virologic failure, implying these variables are independent of each other.
  • The alternative hypothesis ( $H_a$ ) suggests that there is an association, indicating that the type of treatment does affect the rate of virologic failure.

After defining these hypotheses, statistical tests like the Chi-Square Test for Independence are applied to determine which hypothesis the data supports.
Two-Way Table
A two-way table is a vital tool in statistical analysis used to display the frequency distribution of variables and aids in understanding how different factors may be related.

In the given study, a two-way table helps to organize and visualize the results, showing the distribution of virologic failure among women treated with Nevaripine and Lopinavir. The table consists of rows and columns with the following key components:

  • The rows represent different treatment groups: Nevaripine and Lopinavir.
  • The columns represent the outcomes: Virologic Failure and No Virologic Failure.
  • An additional row and column summarize the total counts for each treatment and outcome.

    Utilizing such a layout allows for clearer comparison and aids researchers in identifying potential relationships between treatment types and outcomes.
Virologic Failure
Virologic failure is a critical outcome measure when analyzing the effectiveness of HIV treatment. It occurs when the virus becomes detectable or worsens despite treatment, implying that the therapy is not adequately controlling the HIV infection.
In this study focused on women from sub-Saharan Africa, virologic failure was measured 24 weeks post-treatment initiation. The investigation compared the levels of virologic failure between two groups: those treated with Nevaripine and those with Lopinavir.

Understanding this concept is crucial, as a higher rate of virologic failure suggests that the treatment might not be effective. Such findings prompt healthcare professionals to review and possibly alter treatment protocols for better patient outcomes.
Statistical Analysis
Statistical analysis involves a structured method for examining, organizing, interpreting, and presenting data in a way that allows researchers to draw meaningful conclusions. In this scenario, the Chi-Square Test for Independence was the method chosen to assess whether an independent relationship exists between drug treatment and virologic failure.

To perform a Chi-Square test, follow these general steps:
  • Calculate the expected frequency for each cell in the two-way table assuming independence of variables. This involves multiplying the row total by the column total, then dividing by the grand total.
  • Compute the Chi-Square statistic using the formula:\[ \chi^2 = \sum \frac{(O - E)^2}{E} \]where \(O\) is the observed frequency and \(E\) is the expected frequency.
  • Compare the calculated Chi-Square value to a critical value from a Chi-Square distribution table (based on the desired significance level, often 0.05) to decide whether to reject or fail to reject the null hypothesis.

The outcome of this analysis can provide insights into how effective a treatment is, guiding future medical decisions and policy in healthcare.

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Most popular questions from this chapter

Browsing on the mobile device. A 2012 survey of 2,254 American adults indicates that \(17 \%\) of cell phone owners do their browsing on their phone rather than a computer or other device. (a) According to an online article, a report from a mobile research company indicates that 38 percent of Chinese mobile web users only access the internet through their cell phones. " Conduct a hypothesis test to determine if these data provide strong evidence that the proportion of Americans who only use their cell phones to access the internet is different than the Chinese proportion of \(38 \%\) (b) Interpret the p-value in this context. (c) Calculate a \(95 \%\) confidence interval for the proportion of Americans who access the internet on their cell phones, and interpret the interval in this context.

True or false, Part. II. Determine if the statements below are true or false. For each false statement, suggest an alternative wording to make it a true statement. (a) As the degrees of freedom increases, the mean of the chi-square distribution increases. (b) If you found \(X^{2}=10\) with \(d f=5\) you would fail to reject \(H_{0}\) at the \(5 \%\) significance level. (c) When finding the p-value of a chi-square test, we always shade the tail areas in both tails. (d) As the degrees of freedom increases, the variability of the chi-square distribution decreases.

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