/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Prop 19 in California. In a 2010... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Prop 19 in California. In a 2010 Survey USA poll, \(70 \%\) of the 119 respondents between the ages of 18 and 34 said they would vote in the 2010 general election for Prop \(19,\) which would change California law to legalize marijuana and allow it to be regulated and taxed. At a \(95 \%\) confidence level, this sample has an \(8 \%\) margin of error. Based on this information, determine if the following statements are true or false, and explain your reasoning." (a) We are \(95 \%\) confident that between \(62 \%\) and \(78 \%\) of the California voters in this sample support Prop \(19 .\) (b) We are \(95 \%\) confident that between \(62 \%\) and \(78 \%\) of all California voters between the ages of 18 and 34 support Prop \(19 .\) (c) If we considered many random samples of 119 California voters between the ages of 18 and 34 , and we calculated \(95 \%\) confidence intervals for each, \(95 \%\) of them will include the true population proportion of Californians who support Prop \(19 .\) (d) In order to decrease the margin of error to \(4 \%\), we would need to quadruple (multiply by 4) the sample size. (e) Based on this confidence interval, there is sufficient evidence to conclude that a majority of California voters between the ages of 18 and 34 support Prop \(19 .\)

Short Answer

Expert verified
Statements (b), (c), (d), and (e) are true; statement (a) is false.

Step by step solution

01

Understanding the Problem

We have a poll in which 119 respondents were surveyed, and 70% said they support Prop 19. The margin of error is 8% at a 95% confidence level.
02

Calculating the Confidence Interval

The confidence interval is calculated by taking the sample proportion and adding or subtracting the margin of error. Here, the sample proportion is 70% (or 0.70). The interval is thus \(0.70 \pm 0.08\), which means the interval is from 0.62 to 0.78, or 62% to 78%.
03

Analyzing Statement (a)

Statement (a) claims the confidence interval applies to the sample. Since confidence intervals are used to infer about the population, not the sample, this statement is false.
04

Analyzing Statement (b)

Statement (b) claims about all voters in the target population. The confidence interval does give a range for the true population proportion, so this statement is true.
05

Analyzing Statement (c)

Statement (c) discusses the nature of confidence intervals. It is true because 95% confidence means that, in repeated sampling, 95% of intervals would contain the true population proportion.
06

Analyzing Statement (d)

Statement (d) asks about changing the margin of error. To halve the margin of error, the sample size must be quadrupled. Since \( \text{margin of error} = z \sqrt{\frac{p(1-p)}{n}} \), quadrupling the sample size (\(n\)) does halve the error. Thus, this statement is true.
07

Analyzing Statement (e)

Statement (e) checks if there's evidence of a majority supporting Prop 19. Since the confidence interval (62%-78%) lies above 50%, we can conclude that a majority likely supports it. Hence, this statement is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error in survey research helps us understand how much the results might differ if we were to conduct the same survey multiple times. It is a cushion around the sampled data to give an estimated range of where the real answer lies in the population. Think of it like a safety net that accounts for the tiny inconsistencies that might occur in a sample.

In the context of our example, the margin of error is 8%. This means that while 70% of our sample supports Prop 19, the true level of support in the larger population could reasonably be as low as 62% or as high as 78%.

When we say a result has a margin of error, it essentially tells us the extent to which we can expect the results to fluctuate if we take another sample under the same conditions.
Sample Proportion
The sample proportion is the percentage of people in the sample who have a particular characteristic—in our case, the number of respondents supporting Prop 19. Calculating it is fairly simple. You just need to divide the number of favorable outcomes by the total number of respondents in the sample.

In our survey, 70% of the respondents said they would vote for Prop 19. This is the sample proportion, denoted usually as \( \hat{p} \). It serves as a basis to estimate the population parameter, helping us infer what percentage of all voters might support the proposition.

The sample proportion is fundamental in calculating confidence intervals and understanding the probable reality within the whole population.
Population Proportion
The population proportion is the percentage of all individuals in the population who possess a particular attribute—in this case, support for Prop 19. Unlike the sample proportion, this is what we're ultimately trying to infer from our sample data.

The true population proportion is unknown, and that’s why statistical methods like confidence intervals exist. They help us make educated guesses about this value by using information obtained from the sample.

In our scenario, we're using the sample proportion (70%) and adding or subtracting the margin of error to estimate a range—between 62% and 78%—where the true population proportion likely falls. This practical technique allows researchers to draw meaningful conclusions from samples while considering potential variability.
Sample Size
Sample size refers to the number of respondents or observations included in a survey. Its size plays a crucial role in determining the reliability of the estimates we make about the population.

In this example, we have a sample size of 119. Larger sample sizes generally provide more accurate estimates because they tend to approximate the population more closely. This impacts the margin of error—larger samples typically result in smaller margins of error, allowing for tighter, more precise confidence intervals.

For instance, to reduce the margin of error from 8% to 4%, statement (d) explains that we would need to quadruple our sample size. This is because the margin of error is inversely proportional to the square root of the sample size. Larger samples lead to better estimations of the population proportion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

3.29 Offshore drilling, Part 1. A 2010 survey asked 827 randomly sampled registered voters in California "Do you support? Or do you oppose? Drilling for oil and natural gas off the Coast of California? Or do you not know enough to say?" Below is the distribution of responses, separated based on whether or not the respondent graduated from college. (a) What percent of college graduates and what percent of the non-college graduates in this sample do not know enough to have an opinion on drilling for oil and natural gas off the Coast of California? \begin{tabular}{lcc} & \multicolumn{2}{c} { College Grad } \\ \cline { 2 - 3 } & Yes & No \\ \hline Support & 154 & 132 \\ Oppose & 180 & 126 \\ Do not know & 104 & 131 \\ \hline Total & 438 & 389 \end{tabular} the (b) Conduct a hypothesis test to determine if data provide strong evidence that the proportion of college graduates who do not have an opinion on this issue is different than that of non-college graduates.

Is college worth it? Part. I. Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, \(48 \%\) said they decided not to go to college because they could not afford school. 40 (a) A newspaper article states that only a minority of the Americans who decide not to go to college do so because they cannot afford it and uses the point estimate from this survey as evidence. Conduct a hypothesis test to determine if these data provide strong evidence supporting this statement. (b) Would you expect a confidence interval for the proportion of American adults who decide not to go to college because they cannot afford it to include 0.5? Explain.

Young Americans, Part I. About \(77 \%\) of young adults think they can achieve the American dream. Determine if the following statements are true or false, and explain your reasoning. \(^{27}\) (a) The distribution of sample proportions of young Americans who think they can achieve the American dream in samples of size 20 is left skewed. (b) The distribution of sample proportions of young Americans who think they can achieve the American dream in random samples of size 40 is approximately normal since \(n \geq 30\). (c) A random sample of 60 young Americans where \(85 \%\) think they can achieve the American dream would be considered unusual. (d) A random sample of 120 young Americans where \(85 \%\) think they can achieve the American dream would be considered unusual.

Prenatal vitamins and Autism. Researchers studying the link between prenatal vitamin use and autism surveyed the mothers of a random sample of children aged \(24-60\) months with autism and conducted another separate random sample for children with typical development. The table below shows the number of mothers in each group who did and did not use prenatal vitamins during the three months before pregnancy (periconceptional period). 40 \begin{tabular}{llccc} & \multicolumn{4}{c} { Autism } \\ \cline { 3 - 4 } & & Autism Typical development & Total \\ \cline { 2 - 5 } Periconceptional & No vitamin & 111 & 70 & 181 \\ prenatal vitamin & Vitamin & 143 & 159 & 302 \\ \cline { 2 - 5 } & Total & 254 & 229 & 483 \end{tabular} (a) State appropriate hypotheses to test for independence of use of prenatal vitamins during the three months before pregnancy and autism. (b) Complete the hypothesis test and state an appropriate conclusion. (Reminder: verify any necessary conditions for the test.) (c) A New York Times article reporting on this study was titled "Prenatal Vitamins May Ward Off Autism", Do you find the title of this article to be appropriate? Explain your answer. Additionally, propose an alternative title.

Gender and color preference. A 2001 study asked 1,924 male and 3,666 female undergraduate college students their favorite color. A \(95 \%\) confidence interval for the difference between the proportions of males and females whose favorite color is black ( \(p_{\text {male }}-p\) female \()\) was calculated to be (0.02,0.06) . Based on this information, determine if the following statements are true or false, and explain your reasoning for each statement you identify as false. 2 (a) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) lower to \(6 \%\) higher than the true proportion of females whose favorite color is black. (b) We are \(95 \%\) confident that the true proportion of males whose favorite color is black is \(2 \%\) to \(6 \%\) higher than the true proportion of females whose favorite color is black. (c) \(95 \%\) of random samples will produce \(95 \%\) confidence intervals that include the true difference between the population proportions of males and females whose favorite color is black. (d) We can conclude that there is a significant difference between the proportions of males and females whose favorite color is black and that the difference between the two sample proportions is too large to plausibly be due to chance. (e) The \(95 \%\) confidence interval for \(\left(p_{\text {female }}-p_{\text {male }}\right)\) cannot be calculated with only the information given in this exercise.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.