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Chapter 12: Q35d E (page 385)

At what approximate positions might the following compounds show

IR absorptions?

Short Answer

Expert verified

(d) It shows one distinguishing absorption due to ester at 1735cm-1

Step by step solution

01

Step 1:IR absorption

In general, IR absorption are caused by the interaction between the IR electric field vector and molecular dipole transition related to the molecular vibrations. Absorption is at maximum when the electric field vector and dipole transition moment are parallel to each other.

02

Identify the functional group

Functional groups are groups of one or more atoms with distinctive chemical properties regardless of what is attached to them.

The atoms of functional group are bound by covalent bonds with one another and with rest of the molecule.

The functional group in compound (d) is ester only.

03

Position at which compound show IR absorptions

(c)

(d) Absorption of ester at 1735 cm-1

It shows one distinguishing absorption due to ester at 1735cm-1

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Most popular questions from this chapter

Question: How might you use IR spectroscopy to distinguish between the following pairs of isomers?

a)CH3CH2OHandCH3OCH3b)cyclohexaneand1-hexenec)CH3CH2CO2HandHOCH2CH2CHO

Question: The nitrogen ruleof mass spectrometry says that a compound containing an odd number of nitrogen鈥檚 has an odd-numbered molecular ion.

Conversely, a compound containing an even number of nitrogen鈥檚 has

an even-numbered M+peak. Explain.

Answer questions 6-39 taking all stereoisomers into account.

(a)

(b)

(c)

The infrared spectrum of the compound with the mass spectrum shown below lacks any significant absorption above 3000cm-1 . There is a prominent peak near 1740cm-1 and another strong peak near 1200cm-1 .

Propose a structure consistent with the data.

Question: By knowing the natural abundances of minor isotopes, it鈥檚 possible to

calculate the relative heights of and M+1 peaks. If 13C has a natural

abundance of 1.10%, what are the relative heights of the and

M+1 peaks in the mass spectrum of benzene, C6H6?
See all solutions

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