91Ó°ÊÓ

The hydrolysis with acids can happen when treated with LiAlH₄, there is a reduction of butanoic acid to 1-Butanol. The steps involved are,

$C{H}_{3}C{H}_{2}C{H}_{2}C{O}_{2}H\underset{2.H_3{O}^{+}}{\overset{1.LiAl{H}_4}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}OH$

The hydrolysis with acids can happen when treated with LiAlH₄, there is a reduction of butanoic acid to 1-Butanol. Treat it with PBr₃, there is a conversion of alcohol into 1-bromobutane. The steps involved are,

$C{H}_{3}C{H}_{2}C{H}_{2}C{O}_{2}H\underset{2.H_3{O}^{+}}{\overset{1.LiAl{H}_4}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}OH\underset{}{\overset{PB{r}_3}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br$

The hydrolysis with acids can happen when treated with LiAlH₄, there is a reduction of butanoic acid to 1-Butanol. Treat it with PBr₃, there is a conversion of alcohol into 1-bromobutane. The butanenitrile hydrolysis with aqueous acids results in pentanoic acid formation. The steps involved are,

$\begin{array}{c}C{H}_{3}C{H}_{2}C{H}_{2}C{O}_{2}H\underset{2.H_3{O}^{+}}{\overset{1.LiAl{H}_4}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}OH\stackrel{PB{r}_3}{→}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br\\ \underset{2.H_3{O}^{+}}{\overset{1.NaCN}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}C{O}_{2}H\end{array}$

The hydrolysis with acids can happen when treated with LiAlH₄, there is a reduction of butanoic acid to 1-Butanol. Treat it with PBr₃, there is a conversion of alcohol into 1-bromobutane. Treatment of 1-bromobutane with KOH, eliminates HBr to get 1-butene. The steps involved are,

$\begin{array}{l}C{H}_{3}C{H}_{2}C{H}_{2}C{O}_{2}H\underset{2.H_3{O}^{+}}{\overset{1.LiAl{H}_4}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}OH\stackrel{PB{r}_3}{→}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br\\ \stackrel{alcoholic KOH}{→}C{H}_{3}C{H}_{2}CH=C{H}_2\end{array}$

The hydrolysis with acids can happen when treated with LiAlH₄, there is a reduction of butanoic acid to 1-Butanol. Treat it with PBr₃, there is a conversion of alcohol into 1-bromobutane. The conversion of 1-bromobutane into lithium-dibutyl copper in addition to octane. The steps involved are,

$\begin{array}{l}C{H}_{3}C{H}_{2}C{H}_{2}C{O}_{2}H\underset{2.H_3{O}^{+}}{\overset{1.LiAl{H}_4}{→}}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}OH\stackrel{PB{r}_3}{→}C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br\stackrel{2Li}{→}\\ 2C{H}_{3}C{H}_{2}C{H}_{2}C{H_2}^{-}L{i}^{+}\stackrel{Cul}{→}(C{H}_{3}C{H}_{2}C{H}_{2}C{H}_2{)}_{2}C{u}^{-}L{i}^{+}+C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}Br\\ →C{H}_3(C{H}_2{)}_{6}C{H}_3\end{array}$