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Chapter 15: Q22P (page 477)

Draw and name all possible aromatic compounds with the formula C₈H₉Br.

Short Answer

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Answer

Step by step solution

Step-by-Step SolutionStep 1: Aromatic compounds

There is a possibility of many isomers for the molecular formula C₈H₉Bras it has a benzene ring followed by two extra carbon which can be present in the form of methyl as a substituent and bromine group.

All possible structures and their name

All possible aromatic compounds with the formulaC₈H₉Br are as follows:

(V)1-bromo-3,5-dimethylbenzene (VI)3-bromoethyltoulene

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Most popular questions from this chapter

1-Phenyl-2-butene has an ultraviolet absorption $位_{\max} = 208 鈥� nm$ ( $蔚 = 8000$ ). On treatment with a small amount of strong acid, isomerization occurs and a new substance with $位_{\max} = 250 鈥� nm$ ( $蔚 = 15, 8000$ ) is formed. Propose a structure for this isomer, and suggest a mechanism for its formation.

Draw an energy diagram for the three molecular orbitals of the cyclopropenyl system(C₃H₃). How are these three molecular orbitals occupied in the cyclopropenyl anion, cation, and radical? Which of the three substances is aromatic according to H眉ckel鈥檚 rule?

To be aromatic, a molecule must have 4n+2 p electrons and must have a planar, monocyclic system of conjugation. Cyclodecapentaene fulfills one of these criteria but not the other and has resisted all attempts at synthesis. Explain.