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Chapter 6: Q14E (page 181)

The following alkyl halide can be prepared by the addition of HBr to two different alkenes. Draw the structures of both (reddish-brown 5 Br).

Short Answer

Expert verified

The structure of alkenes is as follows;

H3C-CH2-CH=CH-CH3

H3C-CH2-CH2-CH=CH2

Step by step solution

01

Addition reaction

The reaction in which two or more molecules combine to form a single molecule is called an addition reaction.

02

Addition of HBr to alkene to form alkyl halide

The structure of the given alkyl halide is H3C-CH2-CH2-CH(Br)-CH3. Hence there are two possibilities by which the given alkyl halide is formed;

(a)H3C-CH2-CH=CH-CH3+HBr鈫�H3C-CH2-CH2-CH(Br)-CH3(b)H3C-CH2-CH2-CH=CH2+HBr鈫�H3C-CH2-CH2-CH(Br)-CH3

Using the above two alkene structures, we can get the alkyl halide resultant.

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