/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11P-c Which member in each of the foll... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Q11P-c (page 197)

Which member in each of the following sets ranks higher?

-CH2CH2Bror-CH=CH2

Short Answer

Expert verified

-CH=CH2Ranks higher.

Step by step solution

01

E and Z designation

The cis-trans naming system works only for disubstituted alkenes having two substituents other than hydrogen on the double bond. But when trisubstituted and tetra substitution of the double bond is present then the E and Z system is used for describing alkene stereochemistry.

02

Rule for ranking substituents

  • Consider each of the double-bond carbons separately and ranks the two substituents according to the atomic number of the first atom in each. An atom with a higher atomic number will rank higher.
  • If the first atom same then, look at the second, third, or fourth atoms away from the double-bond until the first difference is found.
  • Multiple-bonded atoms are equivalent to the same number of single bonded atoms.
03

Ranking of given groups

As ranking is atomic number dependent, more the atomic number higher will be ranking. So,-CH=CH2 ranks higher as its carbon has two carbon and one hydrogen attached while-CH2CH2Br has carbon with two hydrogens and one carbon attached.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What about the second step in the electrophilic addition of HCl to an alkene鈥攖he reaction of chloride ion with the carbocation intermediate? Is this step exergonic or endergonic? Does the transition state for this second step resemble the reactant (carbocation) or product (alkyl chloride)? Make a rough drawing of what the transition-state structure might look like.

The sex attractant of the common housefly is an alkene cis鈭�9鈭�tricosenenamed. Draw its structure. (Tricosane is the straight-chain alkaneC23H48.)

Draw structures corresponding to the following IUPAC names:

  1. 3,4-diisopropyl-2,5-dimethyl-3-hexene

Change the following old names to new, post-names, and draw the structure of each compound:

2,5,5-Trimethyl-2-hexene.

Rank the substituents in each of the following sets according to the sequence rules:

-CH2CH3,-C鈮�CH,-C鈮�N,-CH2OCH3
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation

Nuclear Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.