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Magazine Chapter 7: Q20P (page 304)
What are products of the following reactions?
Short Answer
a)
b)
c)
d)
e)
f)
Step by step solution
Some conclusions
1. H2 in presence of Pd/C becomes strong reducing agent and form primary alkane from alkyne.
2. H2 in presence of lindlar catalyst stops the reaction at alkene stage.
3. Na/NH3cannot be used to reduce terminal alkynes, because Na will remove the hydrogen that is attached to the sp carbon of the terminal alkyne.
4. Hydroboration-oxidation= In this anti markoniv addition takes place.
Final answer
a) H2 in presence of Pd/C becomes strong reducing agent and form primary alkane from alkyne.
b) H2 in presence of lindlar catalyst stops the reaction at alkene stage.
c) Na/NH3cannot be used to reduce terminal alkynes, because Na will remove the hydrogen that is attached to the sp carbon of the terminal alkyne.
d)Hydroboration-oxidation= In this anti markoniv addition takes place.
e)Hydroboration-oxidation= In this anti markoniv addition takes place. But here both triple bonded carbon atoms have same number of hydrogen atoms so here two products will form.
f) In presence of H2O and H2SO4 ketone formation is there. But here both triple bonded carbon atoms have same number of hydrogen atoms so here two products will form.
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