/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q-1-35P Compare the electrostatic potent... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Q-1-35P (page 2)

Compare the electrostatic potential maps for methane, ammonia and water. Which is the most polar molecule? Which is the least polar?

Short Answer

Expert verified

Water is the most polar molecule and ammonia is the least polar molecule.

Step by step solution

01

Definition of potential maps

Potential maps are a representation of charge distributions in a molecule. It consists of different colors which signify different charge densities. Red is for the most negative electrostatic potential and blue stands for the most positive electrostatic potential.

02

Comparing the polarity of ammonia, methane, and water.

Methane is non-polar while the other two water and ammonia molecules are polar in nature. So now comparing the polarity of ammonia and water. As the electronegativity difference between oxygen and hydrogen is maximum thus water molecule is the most polar. On the other hand, the electronegativity difference between nitrogen and hydrogen is comparatively lower and thus less polar in nature.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Put a number in each of the blanks.

  1. _ s orbital and _p orbitals form _ SP3orbitals.
  2. _ s orbital and _p orbitals form _SP2orbitals.
  3. _s orbital and颅_p orbitals form _SPorbitals,

Rank the carbanions shown in the margin from most basic to least basic.

HC=C-

H2C=CH-

H3C-CH2-

Draw a Lewis structure for each of the following:

  1. N2H4
  2. CO32-
  3. N2H2
  4. CO2
  5. HOCl

Rank the bonds from the most polar to least polar.

a. C - O,C - F,C - N

b. C - Cl > C - Br > C - I

c. H - O,H - N,H - C

d. C - H,C - C,C - N

An unknown disaccharide gives a positive Tollens鈥� test. A glycosidase hydrolyzes it to d-galactose and d-mannose. When the disaccharide is treated with methyl iodide and Ag2O and then hydrolyzed with dilute HCl, the products are 2,3,4,6-tetra-O-methylgalactose and 2,3,4-tri-O-methylmannose. Propose

a structure for the disaccharide.
See all solutions

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Physical Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.