Chapter 17: Q33P (page 829)
If the preference for formation of a six-membered ring were not so great, what other cyclic product would be formed from the intramolecular aldol addition of
a.2,6-heptanedione? b. 2,8-nonanedione?
Short Answer
a.

b.

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Chapter 17: Q33P (page 829)
If the preference for formation of a six-membered ring were not so great, what other cyclic product would be formed from the intramolecular aldol addition of
a.2,6-heptanedione? b. 2,8-nonanedione?
a.

b.

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Question: Explain why the -hydrogen of an N,N-disubstituted amide is less acidic (pKa= 30) than the hydrogen of an ester (pKa= 25).
A compound known as Hagemann’s estercan be prepared by treating a mixture of formaldehyde and ethyl acetoacetate first with base and then with acid
and heat. Write the structure for the product of each of the steps.
a. The first step is an aldol-like condensation.
b. The second step is a Michael addition.
c. The third step is an intramolecular aldol addition.
d. The final transformation includes a dehydration and a hydrolysis followed by a decarboxylation.

Draw the product of the reaction of each of the following compounds with a base:

What aldol addition product is formed from each of the following compounds?



Problem: starting with bromocyclohexane, how can each of the following compounds be prepared?

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