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How could each of the following compounds be prepared from cyclohexanone?

a.

b.

c.

Short Answer

Expert verified

a.

b.

c.

Step by step solution

01

Step-by-Step SolutionStep 1: Alkylation of the α-carbon in the presence of a strong base (LDA)

The process of alkylation of the α-carbon is done by removing protons present on theα-carbon using a strong base (LDA) and THF solvent. A strong base forms an enolate ion, and then the addition of alkyl halide to the enolate ion takes place.

02

Compound (a) preparation from cyclohexanone

a) The materials for preparing the given compound are cyclohexanone (symmetrical ketone) and 1-bromopropane (alkyl halide). An enolate ion is formed when a cyclohexanone is treated with a strong base LDA and THF solvent. After this, an alkyl halide is added to the enolate ion, where the alkyl group of 1-bromopropane is added to the α-carbon of the cyclohexanone compound.


Formation of alkylated α-carbon compound

03

Compound (b) preparation from cyclohexanone

(b) The given compound is prepared when 3-bromopropene is treated with cyclohexanone (symmetrical ketone). A strong base LDA and THF solvent are added to cyclohexanone, making an enolate ion. In the next step, 3-bromopropene is added to the enolate ion, and the alkyl group of 3-bromopropene is added to the α-carbon of the enolate ion.


Formation of alkylated α-carbon compound

04

Compound (c) preparation from cyclohexanone

(c) The given compound is prepared when benzyl bromide is treated with cyclohexanone (symmetrical ketone). A strong base LDA and THF solvent are added to cyclohexanone, making an enolate ion. After this, benzyl bromide is added to enolate ion, where the alkyl group of benzyl bromide is added to the α-carbon of the cyclohexanone compound.

Formation of alkylated α-carbon compound

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Most popular questions from this chapter

There are other condensation reactions similar to the aldol and claisen condensations:

a. The Perkin condensation is the condensation of an aromatic aldehyde and acetic anhydride. Draw the product obtained from the following Perkin condensation:

b. What compound is formed if water is added to the product of a Perkin condensation?

c. The Knoevenagel condensation is the condensation of an aldehyde or a ketone that has no alpha- hydrogens and a compound such as diethyl malonate that has an alpha-carbon flanked by two electron- withdrawing groups. Draw the product obtained from the following Knoevenagel condensation:

d. What product is obtained when the product of a Knoevenagel condensation is heated in an aqueous acidic solution?

Draw the product of the reaction of each of the following compounds with a base:

Draw the products of the following reactions:

a. diethyl heptanedioate: (1) sodium ethoxide; (2) HCl

b. pentanoic acid + PBr3 + Br2, followed by hydrolysis

c. acetone + LDA/THF: (1) slow addition of ethyl acetate; (2) HCl

d. diethyl 2-ethylhexanedioate: (1) sodium ethoxide; (2) HCl

e. diethyl malonate: (1) sodium ethoxide; (2) isobutyl bromide; (3) HCl, H2O + ∆

f. acetophenone + LDA/THF: (1) slow addition of diethyl carbonate; (2) HCl

Draw the products of the following reactions:

a. 1,3-cyclohexanedione + LDA/THF, followed by allyl bromide

b. g-butyrolactone + LDA/THF, followed by methyl iodide

c. 2,7-octanedione + sodium hydroxide

d. diethyl 1,2-benzenedicarboxylate + sodium ethoxide: (1) slow addition of ethyl acetate; (2) HCl

A compound known as Hagemann’s estercan be prepared by treating a mixture of formaldehyde and ethyl acetoacetate first with base and then with acid

and heat. Write the structure for the product of each of the steps.

a. The first step is an aldol-like condensation.

b. The second step is a Michael addition.

c. The third step is an intramolecular aldol addition.

d. The final transformation includes a dehydration and a hydrolysis followed by a decarboxylation.

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