/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6.21 Which value (if any) corresponds... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Which value (if any) corresponds to a faster reaction: (a) Ea=40kJ/molor Ea=4kJ/mol; (b) a reaction temperature of 0°C or a reaction temperature of 25°C; (c) Keq=10or Keq=100; (d) role="math" localid="1648275832528" ∆H=-10kJ/molor ∆H=10kJ/mol ?

Short Answer

Expert verified

Answer

  1. Ea=4kJ/mol corresponds to a faster reaction.
  2. The temperature 25°Ccorresponds to a faster reaction.
  3. The rate of a reaction is independent of Keq.
  4. The reaction rate is independent of ∆H° .

Step by step solution

01

Step-by-Step SolutionStep 1: Activation energy

The energy barrier that needs to be exceeded for the reactant molecules to convert into products is named the activation energy.

A reaction involving lower activation energy will proceed faster.

02

Factors affecting the rate of a reaction

The factors affecting the rate of a reaction are:

  • Activation energy: A reaction involving lower activation energy will proceed faster.
  • Reactant concentration: Reactant concentration is directly related to the rate of the reaction, i.e., the higher the concentration of the reactants, the faster is the rate of the reaction.
  • Temperature: An increase in temperature leads to an increase in the rate of the reaction.
03

Predicting the reaction rate

  1. The rate of a reaction is inversely proportional to the activation energy of the reaction, and hence the reaction with lower Eacorresponds to a faster reaction.Therefore, Ea=4kJ/mol will correspond to a faster reaction.
  2. Since the rate of reaction shares a direct relation with the temperature of the reaction, the higher temperature among the given two, i.e., 25°Cwill correspond to a faster reaction.
  3. The equilibrium constant does not affect the rate of a reaction.
  4. The rate of a chemical reaction is independent of ∆H° (change in enthalpy).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw an energy diagram for the Brønsted–Lowry acid–base reaction of CH3CO2Hwith role="math" localid="1648461988307" OC(CH3)to form role="math" localid="1648462071427" CH3CO2and (CH3)3COH. Label the axes, starting materials, products, ΔH°, and Ea. Draw the structure of the transition state.

As we will learn in Section 15.12, many antioxidants—compounds that prevent unwanted radical oxidation reactions from occurring—are phenols, compounds that contain an OH group bonded directly to a benzene ring.

  1. Explain why homolysis of the O-H bond in phenol requires considerably less energy than homolysis of the O-H bond in ethanol (362 kJ/mol vs 438 kJ/mol).
  2. Why is the C-O bond in phenol shorter than C-O bond in ethanol?

The following is a concerted, bimolecular reaction:CH3+NaCN→CH3CN+NaBr.

a. What is the rate equation for this reaction?

b. What happens to the rate of the reaction if[CH3Br] is doubled?

c. What happens to the rate of the reaction if [NaCN] is halved?

d. What happens to the rate of the reaction if [CH3Br] and [NaCN] are both increased by a factor of five?

By taking into account electronegativity differences, draw the products formed by heterolysis of the carbon-heteroatom bond in each molecule. Classify the organic reactive intermediate as a carbocation or a carbanion.

Compound A can be converted to either B or C. The energy diagrams for both processes are drawn on the graph below.

  1. Label each reaction as endothermic or exothermic.
  2. Which reaction is faster?
  3. Which reaction generates the product lower in energy?
  4. Which points on the graphs correspond to transition states?
  5. Label the energy of activation for each reaction.
  6. Label the ∆H° for each reaction.
See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.