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Question: Draw the compounds formed when triacylglycerol A is treated with each reagent, forming compounds B and C. Rank A, B, and C in order of increasing melting point.

A.

a. (excess), Pd-C (Compound B)

b. (1 equiv), Pd-C (Compound C)

Short Answer

Expert verified

Answer

Compound B

Compound C

Step by step solution

01

Reduction of a double bond

Triacylglycerols are lipids that contain three fatty acids with some double bonds.Molecular hydrogen and palladium catalysts can cleave the unsaturated double bond and form a saturated single bond.

02

Reaction of triacylglycerols with catalyst

When one equivalent catalyst is used, it can cleave only one double bond, but if the reagent is used in excess, all the double bonds can be cleaved.

Compound B:

Reaction in excess of catalyst

Compound C:

The reaction using only one equivalence of catalyst

03

Order of melting point

As the number of double bonds increases in a compound, its stability decreases, and reactivity increases. Due to decreased stability, physical constants like melting point and boiling point also decrease. Therefore:

Compound A having two double bonds, has the lowest melting point.

Compound B with no double bond has the highest melting point.

Compound C with one double bond has an intermediate melting point.

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