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Magazine Chapter 10: Q.32. (page 419)
Question: What alkylborane is formed from hydroboration of each alkene?
Short Answer
Answer
- (E)-3,5-dimethylhex-2-ene.
- 1-sec-butyl-2-methylcyclopent-1-ene
Step by step solution
Step 1:E-configuration
When there is a double bond in the compound, and the priority groups are present on the different sides of adjacent carbon, it is called E-configuration.
Formation of products
a. The given compound has six carbon atoms in a chain in which the double is present at the C-2 atom. The priority groups are present on different sides of the double bond. Thus, it has E-configuration.
Methyl groups are attached to C-3 and C-5 atoms. The IUPAC name of the given compound is shown below:
(E)-3,5-dimethylhex-2-ene
b. The given compound has five carbon atoms in a cyclic form in which the double is present at C-1 atom. At C-1 atom, the sec-butyl group is attached, and at C-2, the methyl group is attached.
The IUPAC name of the given compound is shown below:
1-sec-butyl-2-methylcyclopent-1-ene
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