/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q70. Question: The following two-step... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q70. (page 380)

Question: The following two-step procedure was used to prepare a sulfide from a diol. Draw theintermediate formed in Reaction [1] and draw a mechanism for Reaction [2].

Short Answer

Expert verified

Answer

The intermediate formed in reaction [1]

The mechanism of reaction [2]

Step by step solution

01

Step-by-Step Solution Step 1: Function of mesyl chloride

Mesyl chloride (CH3SO2Cl)converts alcohol to a good leaving -OMs group.

Addition of mesyl chloride to the alcohol group

02

Mechanism for formation of product

Once the alcohol is converted to the god leaving -OMs group, sodium sulfide can react with any of the two -OMs group. The sulfur then attacks the carbon center of the other -OMs group and leads to the formation of the given product.

SN2 attack of sulfur at the electrophilic carbon center

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: When each halohydrin is treated with NaH a product of molecular formulaC4H8Ois formed. Draw the structure of the product and indicate its stereochemistry.

a.


b.


c.

Question: An allylic alcohol contains an OH group on a carbon atom adjacent to a double bond. The treatment of allylic alcohol A with HCl forms a mixture of two allylic chlorides, B and C. Draw a stepwise mechanism that illustrates how both products are formed.

Question: Draw the product formed when is treated with each reagent.

a.SOCl2, Pyridine

b. TsCl, Pyridine

c. H2SO4

d. HBr

e. PBr3then NaCN

f. POCl3,Pyridine

Question: Draw a stepwise, detailed mechanism for the following reaction.

Question: If the reaction of an alcohol with SOCl2and pyridine follows an SN2 mechanism, what is the stereochemistry of the alkyl chloride formed from (R)-butan-2-ol?
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Chemical Analysis

Read Explanation

Chemical Reactions

Read Explanation

Nuclear Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Organic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.