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Question: Explain the observed trend in the melting points of the following three isomeric alcohols:

(CH3)2CHCH2OH(-108°C),CH3CH2CH2CH2OH(-90°C),(CH3)3COH(26°C)

Short Answer

Expert verified

Answer

The greater symmetry in CH33COHmakes it has a larger melting point than CH32CHCH2OHandCH3CH2CH2CH2OH.

Step by step solution

01

Step-by-Step SolutionStep 1: Melting point

The point at which a particular substance transforms from a solid state to a liquid state is the melting point.Numerous factors influence the melting point, and one among them is the pressure.

02

 Step 2: Isomeric alcohols

Isomeric alcohols are alcohols comprising equivalent molecular formulas but differ in their spatial arrangement. An example of isomeric alcohol is 1-butanol and 2-butanol.

03

Observed trend in the melting points of isomeric alcohols

The melting point of a particular compound is directly proportional to the surface area and symmetry. An increase in surface area or symmetry increases the melting point of the particular compound.

A branched polymer has a lesser surface area in comparison to unbranched primary alcohol.CH32CHCH2OH is branched primary alcohol and CH3CH2CH2CH2OHis an unbranched primary alcohol.

Hence, the melting point of CH3CH2CH2CH2OHis higher thanCH32CHCH2OH .

Because of the greater symmetry in CH33COH, it has a larger melting point thanCH32CHCH2OH and CH3CH2CH2CH2OH.

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