Learning Materials
Features
Discover
Chapter 33: Q. 51 (page 957)
Light from a sodium lamp illuminates a narrow slit and is observed on a screen behind the slit. The distance between the first and third dark fringes is . What is the width (in ) of the slit?
The slit's width of is
Over 30 million students worldwide already upgrade their learning with 91影视!
All the tools & learning materials you need for study success - in one app.
Get started for free
FIGURE Q33.5 shows the light intensity on a viewing screen behind a single slit of width a The light's wavelength is. Is, or is it not possible to tell? Explain
Find an expression for the positions of the first-order fringes of a diffraction grating if the line spacing is large enough for the small-angle approximation to be valid. Your expression should be in terms of and.
. Use your expression from part a to find an expression for the separationon the screen of two fringes that differ in wavelength by.
Rather than a viewing screen, modern spectrometers use detectors-similar to the one in your digital camera-that are divided into pixels. Consider a spectrometer with a grating and a detector with located behind the grating. The resolution of a spectrometer is the smallest wavelength separation that can be measured reliably. What is the resolution of this spectrometer for wavelengths near localid="1649156925210" , in the center of the visible spectrum? You can assume that the fringe due to one specific wavelength is narrow enough to illuminate only one column of pixels.
A triple-slit experiment consists of three narrow slits, equally spaced by distance and illuminated by light of wavelength . Each slit alone produces intensity on the viewing screen at distance.
Consider a point on the distant viewing screen such that the path-length difference between any two adjacent slits is. What is the intensity at this point?
What is the intensity at a point where the path-length difference between any two adjacent slits is?
Light from a helium-neon laser illuminates a circular aperture. It is noted that the diameter of the central maximum on a screen behind the aperture matches the diameter of the geometric image. What is the aperture's diameter (in mm)?
Because sound is a wave, it's possible to make a diffraction grating for sound from a large board of sound-absorbing material with several parallel slits cut for sound to go through. When sound waves pass through such a grating, listeners from the grating report "loud spots" on both sides of center. What is the spacing between the slits? Use for the speed of sound.
What do you think about this solution?
We value your feedback to improve our textbook solutions.
Explanations 
Textbooks 
Flashcards 
91影视 AI 
Notes 
Study Plans 
Study Sets 
Find a degree 
Magazine