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A loudspeaker at the origin emits a 120 Hz tone on a day when the speed of sound is 340 m/s. The phase difference between two points on the x-axis is 5.5 rad. What is the distance between these two points?

Short Answer

Expert verified

The distance between the two points is2.5m.

Step by step solution

01

Given information

The frequency of the wave is 120 Hz.

Speed of sound is 340m/s.

The phase difference between the two points is∆ϕ=5.5rad

02

Wavelength of the wave

The wavelength of the wave is given by λ=vf.

Substituting the given values

λ=340120λ=2.83m

03

The distance between the two points

The phase difference of the waves is given by ∆ϕ=2πλ∆x.

Substitute given values

5.5=2π2.83∆x∆x=2.477∆x≈2.5m

Therefore, the distance between two points is2.5m.

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