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A spherical wave with a wavelength of 2.0 m is emitted from the origin. At one instant of time, the phase at r = 4.0 m is p rad. At that instant, what is the phase at r = 3.5 m and at r = 4.5 m?

Short Answer

Expert verified

The phase at r=3.5mis 12rad.

The phase atr=4.5mis32rad.

Step by step solution

01

Given information

The wavelength of the wave is =2.0m

The phase atr=4.0mis1=rad

02

The phase at r=3.5 m.

The phase difference is given by 2-1=2r2-r1.

Substitute the given values

2-=223.5-4.02=-0.5+2=12rad

Therefore, phase difference atr=3.5mis12rad.

03

The phase at r=4.5 m

Substitute the given values into 2-1=2r2-r1.

2-=224.5-4.02=0.5+2=32rad

Therefore, the phase atr=4.5mis32rad.

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