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Chapter 16: Q. 35 (page 452)

A concert loudspeaker suspended high above the ground emits 35 W of sound power. A small microphone with a 1.0 cm2 area is 50 m from the speaker. a. What is the sound intensity at the position of the microphone? b. How much sound energy impinges on the microphone each second?

Short Answer

Expert verified

a. The sound intensity at the position of the microphone is 1.11脳10-3W.

b. The sound energy impinges on the microphone each second is1.11脳10-7J.

Step by step solution

01

Given information

Sound power is P=35W

Area of microphone is a=1.0cm2=1.0脳10-4m2

Distance between microphone and speaker isr=50m.

02

Part a

The intensity of uniform spherical wave is given by I=Psource4蟺谤2.

Substitute the given values

I=354蟺502I=1.11脳10-3W/m2

Therefore, the sound intensity at the position of the microphone is1.11脳10-3W.

03

Part b

A sound energy impinging on the microphone per second is given by E=Pt=Iat.

Substitute the given values

E=1.11脳10-3脳1.0脳10-4E=1.11脳10-7J

Therefore, the sound energy impinges on the microphone each second is1.11脳10-7J.

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