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Two identical loudspeakers separated by distance ∆xeach

emit sound waves of wavelength λ and amplitude a along the

x-axis. What is the minimum value of the ratio ∆xλ for which

the amplitude of their superposition is also a?

Short Answer

Expert verified

The solution also provides the identical distance of the sound waves of the wavelengths

Step by step solution

01

Discussion on superposition

When two or more waves cross at a point, the displacement at that point is equal to the sum of the displacements of the individual waves.

02

Discusion on the phase difernces

The phrase difference is calculated below

@acos(π∆xλ)=a=cos(π∆xλ)=1/2=A=2aco9s(∆∅2)∆∅=2π∆xλA=2acos(π∆xλ)=π/3∆xλ=1/3

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