/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 69 Two loudspeakers in a plane, 5.0... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 17: Q. 69 (page 486)

Two loudspeakers in a plane, 5.0 m apart, are playing the same frequency. If you stand 12.0 m in front of the plane of the speakers, centered between them, you hear a sound of maximum intensity. As you walk parallel to the plane of the speakers, staying 12.0 m in front of them, you first hear a minimum of sound intensity when you are directly in front of one of the speakers. What is the frequency of the sound? Assume a sound speed of 340 m/s.

Short Answer

Expert verified

The sound emitted by both speakers has the same frequency is170Hz

Step by step solution

01

Description of the frequency of sound

The number of vibrations counted in a second is called frequency. The frequency of sound is 5 cycles per second.

02

Measurement of distance by Pythorogus theroum

The hypotenuse of a triangle can be measured by Pyhogorous theorum where the lengths and breath of a triangle is 12, 5.

122+52=13m

03

Solution of the problems

Difference in path

and the frequency will be

2蟺鈭�蠂位=蟺位=2鈭�蠂=2.1=2mf=u位=3402=170Hz

Hence, the calculated frequency is170Hz

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The lowest note on a grand piano has a frequency of 27.5 Hz. The entire string is 2.00 m long and has a mass of 400 g. The vibrating section of the string is 1.90 m long. What tension is needed to tune this string properly?

The fundamental frequency of an open-open tube is 1500 Hz when the tube is filled with 0掳C helium. What is its frequency when filled with 0掳C air?

Western music uses a musical scale with equal temperament tuning, which means that any two adjacent notes have the same frequency ratio r. That is, notes n and n + 1 are related by fn+1 = r fn for all n. In this system, the frequency doubles every 12notes鈥攁n interval called an octave.

a. What is the value of r?

b. Orchestras tune to the note A, which has a frequency of440 Hz. What is the frequency of the next note of the scale (called A-sharp)?

Noise-canceling headphones are an application of destructive

interference. Each side of the headphones uses a microphone to

pick up noise, delays it slightly, then rebroadcasts the noise next

to your ear where it can interfere with the incoming sound wave

of the noise. Suppose you are sitting 1.8 m from an annoying,

110 Hz buzzing sound. What is the minimum headphone delay, in

ms, that will cancel this noise?

Biologists think that some spiders 鈥渢une鈥� strands of their web to give an enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20 碌m, and spider silk has a density of 1300 kg/m3. To have a fundamental frequency at 100 Hz, to what tension must a spider adjust a 12-cm-long strand of silk?
See all solutions

Recommended explanations on Physics Textbooks

Electromagnetism

Read Explanation

Engineering Physics

Read Explanation

Waves Physics

Read Explanation

Particle Model of Matter

Read Explanation

Electric Charge Field and Potential

Read Explanation

Electrostatics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.