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Chapter 17: Q. 54 (page 486)

The 40-cm-long tube of FIGURE P17.54 has a 40-cm-long insert

that can be pulled in and out. A vibrating tuning fork is held next to the

tube. As the insert is slowly pulled out, the sound from the tuning fork

creates standing waves in the tube when the total length L is 42.5 cm, 56.7 cm, and 70.9 cm. What is the frequency of the tuning fork? Assume vsound = 343 m/s.

Short Answer

Expert verified

The frequency of the tuning fork is 1208 Hz.

Step by step solution

01

The concept of the distance of wavelengths 

The consecutive and equivalent distances between waves are known as wavelength distances.

02

Step 2: 

the distance between three consecutive modes is

位=70.9-42.5=28.4cm=0.284m

Therefore, the frequency is

渭=位f鈬�f=v位-3430.284-1208Hz

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