91影视

The mass of the cylinder = 5kg
The diameter of the cylinder = 60 cm
So radius = 30 cm = 0.3 m

Lets draw the FBD as below

Angular acceleration is calculated by

$伪=\frac{蟿}{I}.............................\left(1\right)$

Torque can be calculated by

$蟿=F脳l................................\left(2\right)$

Where, F is the net force acting on the cylinder and l is the length of arm.

Only force acting is gravitational force

Substitute in equation(2) G = mg

$蟿=mgR......................\left(3\right)$

This is in the shape of disc so use the moment of inertia of disc.

$I=I_{C}M+M{R}^2......................\left(4\right)$

I_CM is the moment of inertia about it center of mass $\frac{M{R}^2}{2}$

Substitute in equation(4) we get

$I=\frac{3M{R}^2}{3}$

Substitute values in equation (1) to get angular acceleration

$$\begin{gathered} 伪=\frac{MgR}{\frac{3}{2}M{R}^2} \\ 伪=\frac{2g}{3R}鈥�鈥�鈥�鈥�鈥�鈥�鈥�鈥�鈥�鈥�.\left(5\right) \end{gathered}$$

Substitute given values in the equation (5) we get

$$\begin{gathered} 伪=\frac{2脳9.8{\mathrm{ms}}^{-2}}{3脳0.3\mathrm{m}} \\ =21.8{\mathrm{rads}}^{-2} \end{gathered}$$

The mass of the cylinder = 5kg
The diameter of the cylinder = 60 cm
So radius = 30 cm = 0.3 m

To calculate the angular speed use the formula below

${蝇}_f^2-{蝇}_i^2=2伪胃,鈥�鈥�鈥�鈥�鈥�鈥�鈥�鈥�鈥�鈥�..\left(6\right)$

Where

蝇_f= final velocity, 蝇_i = initial velocity ,胃 is angular displacement and 伪 is angular displacement.

Substitute values: s the cylinder is below axle so angular displacement ,胃 =蟺/2

蝇_i =0 and 伪 =21.8 rad/s²

$$\begin{gathered} {蝇}_f^2-(0{)}^2=2脳(21.8rad/s^2)脳(蟺/2) \\ {蝇}_f=8.25rad/s \end{gathered}$$