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Chapter 12: Q. 2 (page 330)

A skater holds her arms outstretched as she spins at180rpm . What is the speed of her hands if they are140cm apart?

Short Answer

Expert verified

The speed of the hands of the skater is 13.2m/s

Step by step solution

01

Step 1. Given information

The angular velocity is蝇=180rpm

The diameter is d=140cm.

02

Step 2. Explanation

The relation between the linear velocity and angular velocity is

v=r蝇

Here, v is the linear speed, r is the distance,

Converting the annular speed of the skater from rpm to rad/s.

蝇=180rpm=(180rpm)2蟺rad1rev1min60s=18.84rad/s

The radius and diameter relation.

r=d2r=140cm2=70cm1m100cm=0.7m

The speed of the hands of the skater is

v=r蝇v=(0.7m)(18.84rad/s)=13.195m/s

Therefore, the speed of the hands of the skater is13.2m/s

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