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Chapter 12: Q. 18 (page 331)

In FIGURE EX12.18, what is the net torque about the axle?

Short Answer

Expert verified

The net torque on the pulley about the axle is 鈭�0.20Nm.

Direction of torque is clockwise.

Step by step solution

01

Step 1. Given information

Torque by a force is defined as 蟿=Frsin蠒,

Here 蠒is measured counterclockwise from the r鈫�vector to the F鈫�vector.

02

Step 2. Explanation

The net torque on the pulley about the axle is the torque due to the 30 N force plus the torque due to the 20 N force:

蟿=(30N)r1sin蠒1+(20N)r2sin蠒2=(30N)(0.02m)sin鈭�90掳+(20N)(0.02m)sin90掳=(鈭�0.60Nm)+(0.40Nm)=鈭�0.20Nm

The net torque on the pulley about the axle is鈭�0.20Nm

Direction of torque is clockwise.

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Most popular questions from this chapter

The two blocks in FIGURE CP12.86 are connected by a massless rope that passes over a pulley. The pulley is 12 cm in diameter and has a mass of 2.0 kg. As the pulley turns, friction at the axle exerts a torque of magnitude 0.50 N m. If the blocks are released from rest, how long does it take the 4.0 kg block to reach the floor?

A toy gyroscope has a ring of mass M and radius R attached to the axle by lightweight spokes. The end of the axle is distance R from the center of the ring. The gyroscope is spun at angular velocity v, then the end of the axle is placed on a support that allows the gyroscope to precess. a. Find an expression for the precession frequency 鈩� in terms of M, R, v, and g. b. A 120 g, 8.0-cm-diameter gyroscope is spun at 1000 rpm and allowed to precess. What is the precession period?

The 3.0-m-long, 100 kg rigid beam of FIGURE EX12.31 is supported at each end. An 80 kg student stands 2.0 m from support 1. How much upward force does each support exert on the beam?

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