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Chapter 38: Q. 6 (page 1114)

A photoelectric-effect experiment finds a stopping potential of 1.56Vwhen light of 200nmis used to illuminate the cathode.

a. From what metal is the cathode made?

b. What is the stopping potential if the intensity of the light is doubled?

Short Answer

Expert verified

a. the metal is copper.

b. Stopping potential remains the same.

Step by step solution

01

Part (a) Step 1: Given information

We have given,

stopping potential =1.56V

wavelength =200nm

We have to find the metal from which it is made.

02

Simplify 

We can find the metal using the work function of the metal that is found out as,

W=E-eV0W=1240eV.nm200nm-1.56eVW=4.64eV

Then metal is copper.

03

Part (b) Step 1: Given information

We have given, the intensity of the light is doubled.

We have to find the stopping potential.

04

Simplify  

Since we already know that the stopping potential doesn't depends on the intensity of light. so if we changing the intensity then it doesn't effect the stopping potential.

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Most popular questions from this chapter

FIGURE Q38.12 shows the energy-level diagram of Element X.

a. What is the ionization energy of Element X?

b. An atom in the ground state absorbs a photon, then emits a photon with a wavelength of 1240 nm. What was the energy of the photon that was absorbed?

c. An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion can you draw about the initial kinetic energy of the electron?

What is the energy, in eV, of (a) a 450 MHz radio-frequency photon, (b) a visible-light photon with a wavelength of 450 nm, and (c) an x-ray photon with a wavelength of 0.045 nm?

The electron interference pattern of Figure 38.12 was made by shooting electrons with 50keVof kinetic energy through two slits spaced role="math" localid="1650737433408" 1.0渭尘apart. The fringes were recorded on a detector 1.0mbehind the slits.

a. What was the speed of the electrons? (The speed is large enough to justify using relativity, but for simplicity do this as a nonrelativistic calculation.)

b. Figure 38.12 is greatly magnified. What was the actual spacing on the detector between adjacent bright fringes?

Compton scattering is relevant not only to x-ray photons but, even more so, to higher energy gamma-ray photons. Suppose a350keV gamma-ray photon backscatter (i.e., is scattered back toward the source) from a free electron. Afterward, what is the electron鈥檚 velocity in m/s?

An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has the larger de Broglie wavelength? Explain.
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