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Electrons in a photoelectric-effect experiment emerge from an aluminum surface with a maximum kinetic energy of 1.30 eV. What is the wavelength of the light?

Short Answer

Expert verified

Wavelength of the light is 222.35 nm

Step by step solution

01

Step 1. It is given that electrons emerge from an aluminum surface with a maximum kinetic energy of 1.30 eV 

We need to calculate the wavelength of light.

02

Step 2. Using the expression of maximum kinetic energy.

Kmax=hf-E0f=cKmax=hc-E0hc=Kmax+E0=hcKmax+E0=6.6310-343108m/s1.31.610-19+4.281.610-19=222.35nm

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