/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 3 Electrons in a photoelectric-eff... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Electrons in a photoelectric-effect experiment emerge from an aluminum surface with a maximum kinetic energy of 1.30 eV. What is the wavelength of the light?

Short Answer

Expert verified

Wavelength of the light is 222.35 nm

Step by step solution

01

Step 1. It is given that electrons emerge from an aluminum surface with a maximum kinetic energy of 1.30 eV 

We need to calculate the wavelength of light.

02

Step 2. Using the expression of maximum kinetic energy.

Kmax=hf-E0f=cλKmax=hcλ-E0hcλ=Kmax+E0λ=hcKmax+E0λ=6.63×10-34×3×108m/s1.3×1.6×10-19+4.28×1.6×10-19λ=222.35nm

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

FIGURE Q38.12 shows the energy-level diagram of Element X.

a. What is the ionization energy of Element X?

b. An atom in the ground state absorbs a photon, then emits a photon with a wavelength of 1240 nm. What was the energy of the photon that was absorbed?

c. An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion can you draw about the initial kinetic energy of the electron?

The electron interference pattern of Figure 38.12 was made by shooting electrons with 50keVof kinetic energy through two slits spaced role="math" localid="1650737433408" 1.0μ³¾apart. The fringes were recorded on a detector 1.0mbehind the slits.

a. What was the speed of the electrons? (The speed is large enough to justify using relativity, but for simplicity do this as a nonrelativistic calculation.)

b. Figure 38.12 is greatly magnified. What was the actual spacing on the detector between adjacent bright fringes?

The charge on a muon-a subatomic particle is -e and its mass 207 times that of an electron-

which is confined in a 15-pm-long, one-dimensional box.

(1 pm = 1 picometer = 10-12 m.)

What is the wavelength, in nm, of the photon emitted in a quantum jump from n=2 to n=1

If an electron is in a stationary state of an atom, is the electron at rest? If not, what does the term mean?

The cosmic microwave background radiation is light left over from the Big Bang that has been Doppler-shifted to microwave frequencies by the expansion of the universe. It now fills the universe with 450 photons/cm3 at an average frequency of 160 GHz. How much energy from the cosmic microwave background, in MeV, fills a small apartment that has 95 m2 of floor space and 2.5-m-high ceilings?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.