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Chapter 26: Q. 1 (page 737)

What is the potential difference between xi=10cm and xf=30cm in the uniform electric field Ex=1000V/m?

Short Answer

Expert verified

-200voltsis the potential difference.

Step by step solution

01

Given information and formula used

Given :

xi=10cm ; xf=30cm

Uniform electric field : Ex=1000V/m

Theory used :

The potential decrease is provided by the formula : 鈭�V=-E(xf-xi)

02

Calculating the required the potential difference 

The field is uniform and oriented in the xdirection.

So, using the formula we get :

role="math" localid="1649493329471" 鈭�V=-E(xf-xi)鈬�鈭�V=-200V

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Most popular questions from this chapter

Figure EX26.12 is a graph of Vversusx. Draw the corresponding graph of Exversusx.

Two 3.0-cm-diameter aluminum electrodes are spaced 0.50 mm apart. The electrodes are connected to a 100 V battery.

a. What is the capacitance?

b. What is the magnitude of the charge on each electrode?

A 2.0cm-diameter parallel-plate capacitor with a spacing of 0.50mmis charged to 200V. What are

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(b) the energy density?

a. Which point in Figure EX26.5, 'A' or 'B', has a larger electric potential?

b. What is the potential difference between 'A' and 'B'?

In Problems 75 through 77, you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation (s).

b. Finish the solution to the problem.

76). 400nC=(100V)C

C=8.85脳10-12C2/Nm2(0.10m脳0.10m)d
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