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Chapter 26: Q. 12 (page 738)

Figure EX26.12 is a graph of Vversusx. Draw the corresponding graph of Exversusx.

Short Answer

Expert verified

We've drawn the required graph with slopes5000V/mand-5000V/m

Step by step solution

01

Given information and theory used  

Given :

Theory used :

The electric field is expressed as a function of potential as :

E(x)=-dV(x)dx

02

Drawing the corresponding graph of Ex versus x. 

The potential graph in our situation consists of two lines. As a result, the derivative will be a constant, namely the line's slope. The slopes can be seen to be steep.

5000V/mand-5000V/mare the slopes when drawing the graph. As a result, our graph would look like this:

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