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A neutron is confined in a 10fm-diameter nucleus. If the nucleus is modeled as a one-dimensional rigid box, what is the probability that a neutron in the ground state is less than 2.0fm from the edge of the nucleus?

Short Answer

Expert verified

The probability is9.72%.

Step by step solution

01

Given information 

We know that ,

Diameter =10fm

Neutron at positon =2fm

We have to find the probability of the ground state.

02

Simplify

In general for the ground state for any particle the wave function is given by,

φ(x)=2LsinÏ€³æL

Then, the probability is defines as below with factor of 2 due to neutron is distributed symmetrical around the nucleus.

P=2∫00.2fmφ(x)2dxP=2∫00.2fm2Lsin2Ï€³æLdxP=4L∫00.2fm(1-cos2Ï€³æL)dxP=4Lx-sin2Ï€³æLL2Ï€02fmP=410fm2fm-sin2π×2fm10fm10fm2Ï€P=0.0972P=9.72%

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