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Chapter 42: Q 30 Exercise (page 1236)

What is the total energy (in MeV) released in the beta-minus

decay of 24Na?

Short Answer

Expert verified

Hence, the energy is5.513489MeV

Step by step solution

01

Given information

Δm=0.005919umNa24=23.990961umMg24=23.985042u

02

Explanation

The decay is given as:

Na24→Mg24+e-+v¯

Formula for finding energy is:

E=Δmc2

03

Calculations

Substituting the values:

E=(0.005919u)c2×931.49MeVc21uE=5.513489MeV

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