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91Ó°ÊÓ

Chapter 42: Q 32 Exercise (page 1237)

What is the total energy (in MeV) released in the beta decay

of a neutron?

Short Answer

Expert verified

Therefore, the total energy released is0.78MeV

Step by step solution

01

Given information

Beta decay of a neutron.

02

Explanation

We need to find the energy released during neutron beta decay.

The decay is given as:

n→p++e-+v¯

We find the value of Δm:

Δm=m(n)-mp+-me-Δm=939.57MeV/c2-938.28MeV/c2-0.51MeV/c2Δ³¾=0.78MeV/c2

03

Calculations

The energy released is calculated as:

E=Δmc2E=0.78MeV/c2c2E=0.78MeV

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