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A lead ball is dropped into a lake from a diving board 5.0 m

above the water. After entering the water, it sinks to the bottom with a constant velocity equal to the velocity with which it hit the water. The ball reaches the bottom 3.0 s after it is released. How deep is the lake?

Short Answer

Expert verified

The lake is19.7mdeep.

Step by step solution

01

Given data

Height of the diving board, h=5m

The ball reaches the bottom in time role="math" localid="1648239943091" T=3s.

We have to find the depth dof the lake.

02

Calculation of time taken by the ball to drown.

If we consider the free fall of the lead ball then time needed by the ball to reach the surface of water can be obtained by,

h=12gt2

Therefore, the time needed to reach the surface of the lake,

role="math" localid="1648239398400" t=2hg

Now, the speed of the ball while reaching the water surface is, v=2ghasv2=0+2gh

Time needed by the ball to drown into the lake from the surface,

t'=dvt'=d2gh

03

Calculation of depth

Total time needed to drown the ball into the lake is, T=t+t'

Therefore,

role="math" localid="1648240364972" T=2hg+d2ghd2gh=T-2hgd=T2gh-2hd=32×9.8×5-2×5Takeg=9.8m/s2d=29.7-10d=19.7m

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