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A cheetah spots a Thomson’s gazelle, its preferred prey, and

leaps into action, quickly accelerating to its top speed of 30 m/s, the highest of any land animal. However, a cheetah can maintain this extreme speed for only 15 s before having to let up. The cheetah is 170 m from the gazelle as it reaches top speed, and the gazelle sees the cheetah at just this instant. With negligible reaction time, the gazelle heads directly away from the cheetah, accelerating at 4.6m/s2for 5.0 s, then running at constant speed. Does the gazelle escape? If so, by what distance is the gazelle in front when the cheetah gives up?

Short Answer

Expert verified

The cheetah will give up at 7.5m distance in front of the gazelle.

Step by step solution

01

Given data

The extreme speed possessed by the cheetah, VC=30m/s.

The cheetah can maintain the top speed for a duration of, t=15s.

Initial distance of the gazelle from the cheetah is 170m.

Acceleration of the gazelle, a=4.6m/s2for a time oft'=5s.

02

Determination of the distance travelled by the cheetah

The total distance that the cheetah covered in time tis,

s=VCts=30m/s×15ss=450m

Therefore, the cheetah needs to cover 450-170m=280mto escape.

03

Distance travelled by the gazelle

In time t'=5s, the gazelle escapes at a distance,

x=0+12at'2x=12×4.6×52x=57.5m

The constant speed of the gazelle is,

role="math" localid="1648460424964" vg=atvg=4.6m/s2×5svg=23m/s

Rest of the distance travelled by the gazelle with constant speed in 15-5s=10sis,

d=vgtd=23×10md=230m

In15sthe gazelle covers a distance of230+57.5m=287.5m.

04

Determination of the distance by which the cheetah gave up

The gazelle will led by 287.5-280m=7.5mdistance compare to the cheetah.

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