Q.47 FIGURE P30.47 shows a 1.0-cm-dia... [FREE SOLUTION]

Chapter 30: Q.47 (page 872)

FIGURE P30.47 shows a 1.0-cm-diameter loop with $R = 0.50 惟$ inside a 2.0-cm-diameter solenoid. The solenoid is 8.0cm long, has 120 turns, and carries the current shown in the graph. A positive current is $CW$ when seen from the left. Determine the current in the loop at $t = 0.010 s$

Short Answer

Expert verified

The current induced in the loop is $鈭� 15 渭 A$

Step by step solution

Lenz's Law

Inside this illustration here, we've shown the approach as from left. This power supplied in the thread will create a magnetic field that resisted the variation due to Lenz's law. In our situation, the stream with in circuit will turn around to achieve this need.

Step 2:Current in the loop

Just to see if can have discover its power in the spiral. The solenoid's magnetic field is consistent, and so its value is calculated

B = 渭_{0} I_{sol} \frac{N}{l}

鈥�

A = \frac{1}{4} d^{2} 蟺

$桅 = B A = \frac{1}{4} 渭_{0} I_{sol} \frac{N}{l} d^{2} 蟺$

Faraday's law of induction

$蔚 = 鈭� \frac{螖桅}{螖 t}$

The magnetic flux is the current

$\frac{螖桅}{螖 t} = \frac{1}{4 l} 渭_{0} N d^{2} 蟺 \frac{螖 I_{sol}}{螖 t}$

Ohm's Law

The loop of current using Ohm's law

I_{loop} = \frac{蔚}{R} = 鈭� \frac{1}{4 l R} 渭_{0} N d^{2} 蟺 \frac{螖 I_{sol}}{螖 t} .

The graph depicts the change of piezo power - the charging current. by

$\frac{螖 I_{sol}}{螖 t} = \frac{0.5 A}{0.01 s} = 50 A / s$

$I_{loop} = 鈭� 15 渭 A$

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

91影视

FIGURE P30.47 shows a 1.0-cm-diameter loop with $R = 0.50 惟$ inside a 2.0-cm-diameter solenoid. The solenoid is 8.0cm long, has 120 turns, and carries the current shown in the graph. A positive current is $CW$ when seen from the left. Determine the current in the loop at $t = 0.010 s$

Short Answer

Step by step solution

Lenz's Law

Step 2:Current in the loop

Ohm's Law

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Kinematics Physics

Work Energy and Power

Physics of Motion

Solid State Physics

Conservation of Energy and Momentum

Electrostatics

Study anywhere. Anytime. Across all devices.

91影视

FIGURE P30.47 shows a 1.0-cm-diameter loop with R=0.50惟inside a 2.0-cm-diameter solenoid. The solenoid is 8.0cm long, has 120 turns, and carries the current shown in the graph. A positive current is CWwhen seen from the left. Determine the current in the loop att=0.010s

Short Answer

Step by step solution

Lenz's Law

Step 2:Current in the loop

Ohm's Law

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Kinematics Physics

Work Energy and Power

Physics of Motion

Solid State Physics

Conservation of Energy and Momentum

Electrostatics

Study anywhere. Anytime. Across all devices.

FIGURE P30.47 shows a 1.0-cm-diameter loop with $R = 0.50 惟$ inside a 2.0-cm-diameter solenoid. The solenoid is 8.0cm long, has 120 turns, and carries the current shown in the graph. A positive current is $CW$ when seen from the left. Determine the current in the loop at $t = 0.010 s$