/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.2 I A potential difference of 0.05... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

I A potential difference of 0.050Vis developed across the localid="1650925760420" 10−cmlong wire of FIGURE EX30.2 as it moves through a magnetic field perpendicular to the page. What are the strength and direction(in or out) of the magnetic field?

Short Answer

Expert verified

The strength of magnetic field is0.10T , and the direction is inside the page.

Step by step solution

01

Step 1. Given information

Potential differencee=0.05V

Length of wire=10cm=0.1m

Speed(v)=5.0m/s

Magnetic field is perpendicular to the page.

02

Step 2. Explanation

The potential difference is calculated using the formula

e=lvB0.05=5×0.1×BB=0.1T

To direction of magnetic field has been calculated by the right-hand thumb rule. The positive charge, given in figure, experienced a magnetic force in left direction. The velocity is in upward direction; therefore, by right hand thumb rule, we find that magnetic field direction is inside the page.

The strength of magnetic field is 0.10T, and the direction is inside the page.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

66. II FIGURE P30.66 shows the current through a10mH inductor. Draw a graph showing the potential differenceΔVL across the inductor for these6ms .

The magnetic field at one place on the earth's surface is 55μTin strength and tilted 60∘down from horizontal. A 200 turn coil having a diameter of 4.0 cm and a resistance of 2.0Ωis connected to a 1.0μFcapacitor rather than to a current meter. The coil is held in a horizontal plane and the capacitor is discharged. Then the coil is quickly rotated 180∘so that the side that had been facing up is now facing down. Afterward, what is the voltage across the capacitor?

I

I The metal equilateral triangle in FIGURE EX30.11,20cmon each side, is halfway into a0.10Tmagnetic field.

a. What is the magnetic flux through the triangle?

b. If the magnetic field strength decreases, what is the direction of the induced current in the triangle?

Your camping buddy has an idea for a light to go inside your tent. He happens to have a powerful and heavy horseshoe magnet that he bought at a surplus store. This magnet creates a 0.20Tfield between two pole tips 10cmapart. His idea is to build the hand-cranked generator shown in FIGURE .He thinks you can make enough current to fully light a 1.0Ωlightbulb rated at 4.0W. That’s not super bright, but it should be plenty of light for routine activities in the tent.

a. Find an expression for the induced current as a function of time if you turn the crank at frequency f. Assume that the semicircle is at its highest point at t=0s.

b. With what frequency will you have to turn the crank for the maximum current to fully light the bulb? Is this feasible?

21. Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. The electric field strength1.5m from the center of the circle is4.0mV/m . At what rate is the magnetic field changing?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.