91影视

A magnetic flux $\mathrm{桅}$seems to be the magnitude of magnetic field which passes through some kind of ring of area $A$. If the magnetic field lies straight towards the plane's normal, This magnetic flux was provided by

${\mathrm{桅}}_m=BA$ $\left(1\right)$

The magnetic flux, however, would be supplied by if the magnetic field forms an angular position only with planes.

${\mathrm{桅}}_{\mathrm{m}}=BA\cos 鈦�胃$ $\left(2\right)$

The entire area of a triangle is equal to half of it's own base times its height. The Pythagoras equation is used to compute the altitude.

$h=\sqrt{(8\mathrm{cm}{)}^2鈭�(4\mathrm{cm}{)}^2}=4\sqrt{3}\mathrm{cm}$

Therefore the area of a triangle,

$A=\frac{1}{2}bh=\frac{1}{2}\left(0.08\mathrm{m}\right)\left(4\sqrt{3}脳{10}^{鈭�2}\mathrm{m}\right)=2.77脳{10}^{鈭�3}{\mathrm{m}}^2$

Then align the equation $\left(2\right)$for localid="1648903666492" $胃$to obtain

$胃={\cos }^{鈭�1}鈦�\left(\frac{{\mathrm{桅}}_{\mathrm{m}}}{BA}\right)$ (3)

Then put the data for $A$,${\mathrm{桅}}_m$and $B$to the equation(3) to obtain role="math" localid="1648903903568" $胃$

$胃={\cos }^{鈭�1}鈦�\left(\frac{{\mathrm{桅}}_{\mathrm{m}}}{BA}\right)$

$={\cos }^{鈭�1}鈦�\left(\frac{6脳{10}^{鈭�6}\mathrm{Wb}}{\left(5脳{10}^{鈭�3}\mathrm{T}\right)\left(2.77脳{10}^{鈭�3}{\mathrm{m}}^2\right)}\right)$

$={64}^{鈭�}$