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What electric field strength and direction will allow the proton in FIGURE P31.30 to pass through this region of space without being deflected?

Short Answer

Expert verified

The region of space without being deflectedE=2×105V/m

Step by step solution

01

Given

v=2×107m/s

B=0.01T

02

Right Hand Rule

Magnetic force occurs downward if using its right hand rule.

As a reason, due to the electric field, equal and opposite charges exist upward, but electron are not deflected. As a function, the direction of the electric field is also downward.

Fe=FB

qE=qvB

E=vB

E=2×107×10−2

E=2×105V/m

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Most popular questions from this chapter

FIGUREP31.39Shows the electric field inside a cylinder of radius localid="1649879543758" R=3.0mm.. The field strength is increasing with time as localid="1649879549377" E=1.0×108t2V/m, where tis in s. The electric field outside the cylinder is always zero, and the field inside the cylinder was zero for localid="1649879554833" t<0.

localid="1649879566359" a.Find an expression for the electric flux localid="1649879560575" ϕethrough the entire cylinder as a function of time.

localid="1649879572467" b. Draw a picture showing the magnetic field lines inside and outside the cylinder. Be sure to include arrowheads showing the field’s direction.

localid="1649879587867" c. Find an expression for the magnetic field strength as a function of time at a distance localid="1649879577475" r<Rfrom the center. Evaluate the magnetic field strength atlocalid="1649879582437" r=2.0mm, localid="1649879592577" t=2.0s.

d. Find an expression for the magnetic field strength as a function of time at a distancelocalid="1649879597467" r>Rfrom the center. Evaluate the magnetic field strength at localid="1649879602321" r=4.0mm, localid="1649879607075" t=2.0s.

A radio receiver can detect signals with electric field amplitudes as small as 300μ³Õ/m. What is the intensity of the smallest detectable signal?

FIGUREP31.38shows the voltage across a 0.10mFcapacitor. Draw a graph showing the displacement current through the capacitor as a function of time.


Show that the displacement current inside a parallel-plate capacitor can be written CdVCcdt.

Is the electric field strength in FIGUREQ31.5increasing, decreasing, or not changing? Explain.

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