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What electric field strength and direction will allow the proton in FIGURE P31.30 to pass through this region of space without being deflected?

Short Answer

Expert verified

The region of space without being deflectedE=2×105V/m

Step by step solution

01

Given

v=2×107m/s

B=0.01T

02

Right Hand Rule

Magnetic force occurs downward if using its right hand rule.

As a reason, due to the electric field, equal and opposite charges exist upward, but electron are not deflected. As a function, the direction of the electric field is also downward.

Fe=FB

qE=qvB

E=vB

E=2×107×10−2

E=2×105V/m

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Most popular questions from this chapter

Do the situations in FIGURE represent possible electromagnetic waves? If not, why not?

FIGUREP31.39Shows the electric field inside a cylinder of radius localid="1649879543758" R=3.0mm.. The field strength is increasing with time as localid="1649879549377" E=1.0×108t2V/m, where tis in s. The electric field outside the cylinder is always zero, and the field inside the cylinder was zero for localid="1649879554833" t<0.

localid="1649879566359" a.Find an expression for the electric flux localid="1649879560575" ϕethrough the entire cylinder as a function of time.

localid="1649879572467" b. Draw a picture showing the magnetic field lines inside and outside the cylinder. Be sure to include arrowheads showing the field’s direction.

localid="1649879587867" c. Find an expression for the magnetic field strength as a function of time at a distance localid="1649879577475" r<Rfrom the center. Evaluate the magnetic field strength atlocalid="1649879582437" r=2.0mm, localid="1649879592577" t=2.0s.

d. Find an expression for the magnetic field strength as a function of time at a distancelocalid="1649879597467" r>Rfrom the center. Evaluate the magnetic field strength at localid="1649879602321" r=4.0mm, localid="1649879607075" t=2.0s.

The intensity of an electromagnetic wave is 10W/m2. What will the intensity be if:

a. The amplitude of the electric field is doubled?

b. The amplitude of the magnetic field is doubled?

c. The amplitudes of both the electric and the magnetic fields are doubled?

d. The frequency is doubled?

A helium-neon laser emits a 1.0-mm-diameter laser beam with a power of 1.0mW. What are the amplitudes of the electric and magnetic fields of the light wave?

In reading the instruction manual that came with your garagedoor opener, you see that the transmitter unit in your car produces a250mW,350MHzsignal and that the receiver unit is supposed to respond to a radio wave at this frequency if the electric field amplitude exceeds0.10V/m. You wonder if this is really true. To find out, you put fresh batteries in the transmitter and start walking away from your garage while opening and closing the door. Your garage door finally fails to respond when you're 42maway. What is the electric field amplitude at the receiver when it first fails??

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