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What is the force (magnitude and direction) on the proton in FIGURE P31.29? Give the direction as an angle CWor cCWfrom vertical.

Short Answer

Expert verified

The force, FB=1.61013N

The force, Fe=1.61013N

The net force,Fnet=2.261013N

Step by step solution

01

Find the direction of electrostatic force.

With in presence of an electric field, there is an electrostatic force called FE.

02

Find FB, Fe, Fnet 

The magnetic force flows north and use the right - hand principle.

Calculate FB

localid="1648970948872" FB=qvB

FB=1.610191070.1 ( enter the quantities in the formula)

FB=1.61013N

Calculate localid="1648971852105" Fe

localid="1648971000005" Fe=eE

Fe=1.61019106 ( enter the quantities in the formula)

Fe=1.61013N

Calculate Fnet

localid="1648971062338" Fnet=FB2+Fe2

Fnet=2FB

Fnet=21.61013 ( enter the quantities in the formula)

Fnet=2.261013N

03

Find direction and θ

To find the direction and

tan=FBFe

tan=1.610131.61013 ( enter the quantities in the formula)

tan=1=45

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