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Chapter 31: Q. 28 (page 902)

What are the electric field strength and direction at the position of the electron in FIGURE $P 31.28$ $?$

Short Answer

Expert verified

Electric field strength in figure $P 31.8$ is $1.75 脳 10^{6} V / m$ , $F_{E_{}}$ isrole="math" localid="1648932697397" $2.8 脳 10^{- 13} N$ and $F_{B}$ is $1.6 脳 10^{13} N$

Step by step solution

01

Figure for direction of electric field intensity is depicted.

Figure is,

The figure on the page has come to an end is,

02

Calculation for force

Magnetic and electric fields both produce force:

$\tan (30 掳) = \frac{F_{B}}{F_{E}}$

A magnetic force occurs upward when utilizing the right hand rule.

$F_{B} = qvB$

$F_{B} = 1.6 脳 10^{- 19} 脳 10^{7} 脳 0.1$

$F_{B} = 1.6 脳 10^{- 13} N$

For $F_{E}$ :

$\tan (30 掳) = \frac{F_{B}}{F_{E}} = \frac{1.6 脳 10^{13}}{F_{E}}$

$F_{E} = \frac{1.6 脳 10^{- 13}}{0.57}$

$F_{E} = 2.8 脳 10^{- 13} N$

03

Calculation for electric field strength

Strength of the electric field,

$F_{E} = qE$

$E = \frac{F_{E}}{q}$

$F_{E}$ -Force of electric field

$q$ -charge

$E = \frac{2.8 脳 10^{- 13}}{1.6 脳 10^{- 19}}$

localid="1648932420433" $E = 1.75 脳 10^{6} V / m$

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Most popular questions from this chapter

$F I G U R E P 31.39$ Shows the electric field inside a cylinder of radius localid="1649879543758" $R = 3.0 m m .$ . The field strength is increasing with time as localid="1649879549377" $E = 1.0 脳 10^{8} t^{2} V / m$ , where $t$ is in $s$ . The electric field outside the cylinder is always zero, and the field inside the cylinder was zero for localid="1649879554833" $t < 0$ .

localid="1649879566359" $a .$ Find an expression for the electric flux localid="1649879560575" $蠒_{e}$ through the entire cylinder as a function of time.

localid="1649879572467" $b$ . Draw a picture showing the magnetic field lines inside and outside the cylinder. Be sure to include arrowheads showing the field鈥檚 direction.

localid="1649879587867" $c$ . Find an expression for the magnetic field strength as a function of time at a distance localid="1649879577475" $r < R$ from the center. Evaluate the magnetic field strength atlocalid="1649879582437" $r = 2.0 m m$ , localid="1649879592577" $t = 2.0 s$ .

d. Find an expression for the magnetic field strength as a function of time at a distancelocalid="1649879597467" $r > R$ from the center. Evaluate the magnetic field strength at localid="1649879602321" $r = 4.0 m m$ , localid="1649879607075" $t = 2.0 s$ .

In reading the instruction manual that came with your garagedoor opener, you see that the transmitter unit in your car produces a $250 mW, 350 MHz$ signal and that the receiver unit is supposed to respond to a radio wave at this frequency if the electric field amplitude exceeds $0.10 V / m$ . You wonder if this is really true. To find out, you put fresh batteries in the transmitter and start walking away from your garage while opening and closing the door. Your garage door finally fails to respond when you're $42 m$ away. What is the electric field amplitude at the receiver when it first fails $?$ $?$

Do the situations in FIGURE represent possible electromagnetic waves? If not, why not?

Only $25 %$ of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter?

You've recently read about a chemical laser that generates a $20 - cm$ -diameter, $25 MW$ laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a $20 - cm$ -diameter, $100 kg$ , perfectly absorbing block. What speed would such a block have if pushed horizontally $100 m$ along a frictionless track by such a laser $?$

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