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The magnetic field of an electromagnetic wave in a vacuum isBz=(3.00μ°Õ)sin1.00×107x-Ó¬³Ù , where x is in m and t is in s. What are the wave's (a) wavelength, (b) frequency, and (c) electric field amplitude?

Short Answer

Expert verified

a.Wave length of EM wave is6.28×10-7m.

b.Frequency of EM wave is4.775×1014Hz.

c. Electric field amplitude of EM wave is900V/m.

Step by step solution

01

Calculation for Wavelength of EM waves (part a)

(a).

As it stands,

c=3×108m/s

Bz=(3.00μ°Õ)sin1.00×107x-Ó¬³Ù

Wavelength is,

λ=2π1×107m

λ=2π×10-7m

λ≈6.28×10-7m

02

Calculation for frequency for EM waves (part b)

(b).

Frequency is,

c=f·λ

Both should be divided bylocalid="1648798271555" λ,

cλ=f·λλλ

f≈cλ

f≈3×108m/s2π×10-7m

f≈4.775×1014Hz

03

Calculation for electric field amplitude of EM waves (part c)

(c).

As it stands,

Bz=(3.00μ°Õ)sin1.00×107x-Ó¬³Ù

=Bsin1.00×107x-Ó¬³Ù

|E|=c|B|

|E|=3×108m/s×3μ°Õ

|E|=900V/m

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